COSMOS Chapter 6 Solution 99 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2020
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1
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Hundebuchesn

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 99. FBD Frame: ( 0.3 m ) Dx = − ( 0.4 m ) ( 900 N ) = 0, ΣM A = 0: Dx = 1200 N D x = 1.200 kN ΣFx = 0: 1.200 kN − Ax = 0, ΣFy = 0: Ax = 1.200 kN, A x = 1.200 kN Ay − 900 N = 0 A y = 900 N Note: AG is a two-force member. ( 0.2 m )  By − ( 0.4 m ) ( 900 N ) = 0, ΣM A = 0: FBD AC: ΣFy = 0: 900 N + 1800 N − 900 N − ( FAGx = 2400 N, FAG = 3000 N ΣFx = 0: − ΣM E = 0: ΣFx = 0: FBD DF: ΣFy = 0: 3 FAG = 0 5 FAGy = 1800 N 4 ( 3000 N ) − 1200 N + Bx = 0, 5 On GBEH: By = 1800 N G x = 2.40 kN , B x = 3.60 kN , ) Bx = 3600 N G y = 1.800 kN ! B y = 1.800 kN 3 FDH = 0, 5 1200 N − Ex = 0 − ( 0.2 m ) ! FDH = 0 Ex = 1200 N Ey = 0 On GBEH: E x = 1.200 kN H x = 0, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. , Ey = 0 ! Hy = 0 !

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