University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

189

Pages:

2
Author:

Campbell Wagner

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 101. The equivalent force-couple system at A for each of the five force-couple systems will be determined and compared to F = ( 2 lb ) j M = ( 48 lb ⋅ in.) i + ( 32 lb ⋅ in.) k To determine if they are equivalent Force-couple system at B: Have ΣF : F = ( 2 lb ) j and ΣM A : M = ΣM B + rB/ A × FB ( ) M = ( 32 lb ⋅ in.) i + (16 lb ⋅ in.) k + ( 8 in.) i × ( 2 lb ) j = ( 32 lb ⋅ in.) i + ( 32 lb ⋅ in.) k ∴ is not equivalent Force-couple system at C: Have ΣF : And ΣM A : F = ( 2 lb ) j ( M = M C + rC/ A × FC ) M = ( 68 lb ⋅ in.) i + ( 8 in.) i + (10 in.) k  × ( 2 lb ) j = ( 48 lb ⋅ in.) i + (16 lb ⋅ in.) k ∴ is not equivalent continued . COSMOS: Complete Online Solutions Manual Organization System Force-couple system at E: Have ΣF : F = ( 2 lb ) j and ΣM A : M = M E + rE/ A × FE ( ) M = ( 48 lb ⋅ in.) i + (16 in.) i − ( 3.2 in.) j × ( 2 lb ) j = ( 48 lb ⋅ in.) i + ( 32 lb ⋅ in.) k ∴ is equivalent Force-couple system at G: Have ΣF : F = ( 2 lb ) i + ( 2 lb ) j F has two force components ∴ is not equivalent Force-couple system at I: Have ΣF : F = ( 2 lb ) j and ΣM A : ΣM I + rI / A × FI ( ) M = ( 80 lb ⋅ in.) i − (16 in.) k + (16 in.) i − ( 8 in.) j + (16 in.) k  × ( 2 lb ) j M = ( 48 lb ⋅ in.) i + (16 lb ⋅ in.) k ∴ is not equivalent .