University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

300

Pages:

1
Author:

salcignofi13

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 61. FBD Cylinder: ( ) W = ( 80 kg ) 9.81 m/s 2 = 784.8 N For impending slip at B, ΣM A = 0: FB = µ sB N B = 0.30 N B ( r cos 30° ) N B − r (1 + sin 30° )( 0.30 N B ) − r sin 30°W = 0 N B = 1.20185W = 943.21 N FB = 0.30 N B = 0.36055W ΣM G = 0: ΣFx = 0: r ( FA − FB ) = 0, FA = FB = 0.36055W N A sin 30° + FA cos30° − N B = 0 NA = − ( 0.36055W ) cos30° + 1.20185W sin 30° N A = 1.77920W For minimum µ A , slip impends at A, so µ A min = FA 0.36055W = = 0.2026 N A 1.77920W µ A min = 0.203 Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.