COSMOS Chapter 9 Solution 126 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

79

Pages:

1
Author:

Tyshawn Shaffer

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 126. r 2 = y 2 + z 2 = kx : x = h, At Thus, r 2 = r = a; = Now So dI y = dI y′ + x 2dm = h a2 a2 xdx h h ∫ 0 dm = ρπ h ∫ 0 xdx 1 ρπ a 2h 2  1 a2  1 2 r dm + x 2dm =  x + x 2  dm 4 4 h  = ρπ  a2 h  1 a2 2 x + x3  dx ∫ 0  h 4 h  = ρπ a 2  1 a 2 h3 h 4  +   h  4 h 3 4  1 ρπ a 2h a 2 + 3h 2 12 1 m = ρπ a 2h 2 ( ) 1 1 I y =  ρπ a 2h  a 2 + 3h 2 2 6 ( And a2 h 2  a2 h h 1 a I y = ∫ 0 dI y = ∫ 0  x + x 2 ρπ xdx h 4 h  = Recall: k= a2 x h Have dm = ρπ r 2dx = ρπ Then m = a 2 = kh; k y2 = Iy m ( = a 2 + 3h 2 ) 6 ) ( or I y = m a 2 + 3h 2 or ky = ( 2 + 3h 2 ) 6 ) 6

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