COSMOS Chapter 9 Solution 133 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

115

Pages:

2
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 133. First note and Now L L − 240 = 120 80 or L = 720 mm m = ρ stV 2 1  π m1 = ρ st  π a12h1  = × 7850 kg/m 3 × ( 0.120 m ) ( 0.720 m ) 3 3   = 85.230 kg 3 2  2 m2 = ρ st  π a23  = π × 7850 kg/m 3 × ( 0.090 m ) = 11.9855 kg 3  3 2 1  π m3 = ρ st  π a32h3  = × 7850 kg/m 3 × ( 0.080 m ) ( 0.720 − 0.240 ) m 3  3 = 25.253 kg Now ( )1 − ( I y )2 − ( I y )3 Iy = Iy continued COSMOS: Complete Online Solutions Manual Organization System ( IGG′ )cup ( I AA′ )cup (b) Have or = 0.01 5 5  mcup a 2 = 0.01mcup  a 2 + 2la + l 2  12 3  Now let ζ = ( From Part a ) a l Then 5  5ζ 2 = 0.12  ζ 2 + 2ζ + 1 3  or 40ζ 2 − 2ζ − 1 = 0 Then or ζ = 2± ζ = 0.1851 ( −2 )2 − 4 ( 40 )( −1) 2 ( 40 ) and ζ = − 0.1351 ∴ a = 0.1851 l

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