COSMOS Chapter 3 Solution 146 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
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221

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1
Author:

santjinlmr

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 146. M O = rA/O × TBA Based on where M O = M xi + M y j + M zk = M xi + (100 lb ⋅ ft ) j − ( 400 lb ⋅ ft ) k rA/O = ( 6 ft ) i + ( 4 ft ) j TBA = λ BATBA = ( 6 ft ) i − (12 ft ) j − ( a ) k T BA d BA i j k T ∴ M xi + 100 j − 400k = 6 4 0 BA d 6 −12 −a BA = TBA  − ( 4a ) i + ( 6a ) j − ( 96 ) k  d BA  100 d BA 6a From j-coefficient: 100d AB = 6aTBA or TBA = From k -coefficient: −400d AB = −96TBA or TBA = Equating Equations (1) and (2) yields a= 400 d BA 96 100 ( 96 ) 6 ( 400 ) or a = 4.00 ft . (1) (2)

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