COSMOS Chapter 6 Solution 82 | Answer Key - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2023
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COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 82. FBD Frame: ΣM A = 0:  2  180 N  = 0  2  ( 0.2 m ) Bx − ( 0.36 m )  Bx = 162 2 N, Ax = 252 2 N, ΣM C = 0: A x = 356 N W 2 (180 N ) = 0 2 B y = 127.3 N B y = 90 2 N, FBD member ABD: W 2 (180 N ) = 0 2 ΣFx = 0: −162 2 N + Ax − ΣFy = 0: By − B x = 229 N ( 0.20 m ) ( 252 ) ( 2 N − ( 0.08 m ) 90 2 N − ( 0.20 m ) D = 0, W ) D = 216 2 N D = 305 N W ΣFx = 0: 252 2 N − 162 2 N − C x = 0 Cx = 90 2 N, C x = 127.3 N W ΣFy = 0: 90 2 N + C y − 216 2 N = 0 C y = 126 2 N, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. C y = 178.2 N W

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