University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

232

Pages:

1
Author:

FrextWhestembki

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 142. FBD wheel: ΣM E = 0: M E = ( 7.5 in.)(T2 − T1 ) or FBD lever: ΣM C = 0: Impending slipping: So ( 4 in.)(T1 + T2 ) − (16 in.)( 25 lb ) = 0 T1 + T2 = 100 lb or or − M E + ( 7.5 in.)(T2 − T1 ) = 0 T2 = T1e µs β T2 = T1e ( ) 0.25 32π = 3.2482T1 T1 (1 + 3.2482 ) = 100 lb T1 = 23.539 lb and M E = ( 7.5 in.)( 3.2482 − 1)( 23.539 lb ) = 396.9 lb ⋅ in. M E = 397 lb ⋅ in. W Changing the direction of rotation will change the direction of M E and will switch the magnitudes of T1 and T2 . The magnitude of the couple applied will not change. W Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.