COSMOS Chapter 8 Solution 41 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2020
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1
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omiliar74be

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 41. FBD Rod: ΣM A = 0: ( 20 in.) N1 − (12.5 in.)(12 lb ) = 0 N1 = 7.5 lb. FBD Cylinder: ΣFy = 0: N 2 − 7.5 lb − 36 lb = 0, N 2 = 43.5 lb since µ1 = µ2 and N1 < N 2 , slip will impend at top of cylinder first, so F1 = µ s N1 . F1 = 0.35 ( 7.5 lb ) = 2.625 lb ΣM D = 0: ( 4.25 in.) P − (12.5 in.)( 2.625 lb ) = 0, P = 7.7206 lb Pmax = 7.72 lb W To check slip analysis above, ΣFy = 0: N 2 − 36 lb − 7.5 lb = 0 N 2 = 43.5 lb F2max = µ s N 2 = 0.35 ( 43.5 lb ) = 15.225 lb ΣFx = 0: P − F1 − F2 = 0, 7.72 lb − 2.625 lb − F2 = 0 F2 = 5.095 lb < Fmax , Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. OK

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