University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

292

Pages:

1
Author:

Lily Callahan

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 117. Geometry and force rotation: Let EBC = α = cos −1 50 mm = 60° = 100 mm s DBE , FAE , GAE Then contact angles are β B = 360° − 120° = 240° = upper cylinder, and β A = 30° = π 6 4π rad for cord on 3 rad for each cord contact on lower cylinder. Let the force in section FC = TF Let the force in section DG = TG With A fixed and the cord moving, TG = We µk β A = We ( ) 0.25 π6 = 1.13985W For maximum W, slip impends on drum B, so TB = TF e µs β B or TF = TG e− µs β B TF = 1.13985We ( ) −0.30 43π = 0.32441W For slip at F W1 = TF e µk β A = 0.32441We ( ) 0.25 π6 = 0.36978W so W = 2.7043W1 and m = 2.7043 in. = 2.7043 ( 75 kg ) m = 203 kg Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS Chapter 8 Solution 117

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