University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

164

Pages:

1
Author:

hacedoras1kxy

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 78. FBD Frame: ΣM A = 0: ( 0.25 m ) Dx − ( 0.95 m )( 480 N ) = 0 D x = 1824 N W E x = 1824 N W FBD member DF: Note that BE is a two-force member, Ex = Ey ΣFx = 0: −1824 N + Ex = 0, so ΣM D = 0: ΣFy = 0: E y = 1824 N W ( 0.50 m )(1824 N ) − ( 0.75 m ) C + ( 0.95 m )( 480 N ) = 0 C = 1824 N W D y = 480 N W − D y + 1824 N − 1824 N + 480 N = 0 Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS Chapter 6 Solution 78

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