University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
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345

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2
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teespagmaxrtf

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 20. At x = 0: b = c cos ( 0 ) First note: c=b or At x = 2a : b = b sin k ( 2a ) 2ka = or k= π 2 π 4a π π  2a  A = ∫ a  b sin x − b cos x  dx 4a 4a   Then 2a π 4a π   4a x− sin x = b  − cos 4a π 4a  a  π =− = Have 4ab  1   1 + (1) −   π  2   2 4ab π ( ) 2 −1 I y = ∫ x 2dA π 2 a b sin 4a x 2 x dydx a b cos π x 4a = ∫ ∫ = 2a 2   ∫ a x  b sin 4a x − b cos 4a x  dx π  π  continued COSMOS: Complete Online Solutions Manual Organization System     2 π 2 π x π   2x = b  sin x + cos x − cos x 2 3  π  4a 4a 4a  π    π        4a   4a    4a   2a     2 2x π 2 π x π  − cos x − sin x + sin x  3   π 2 π  4a 4a 4a   π           4a   4a    4a    a 2a 64a3b  π π  π   π π  π 2 2  − + + − Iy = sin x cos x x sin x cos x 2 x         4a  2a   4a 4a   π 3  4a 16a 2   a =  64a3b   π 2    1 1  π 2    1 π + 1 2 − − + 2 − ( )( ) ( )             4    2 16    π 3   2     I y = 1.482a3b = 1.48228a3b And ky = = Iy A 1.48228a3b 4ab 2 −1 π ( = 1.676a ) k y = 1.676a

COSMOS Chapter 9 Solution 20

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