COSMOS: Complete Online Solutions Manual Organization System
Chapter 3, Solution 23.
Have
M O = rA/O × R
where
rA/D = ( 30 ft ) j + ( 3 ft ) k
T1 = − ( 62 lb ) cos10° i − ( 62 lb ) sin10° j
= − ( 61.058 lb ) i − (10.766 lb ) j
JJJG
AB
T2 = T2
AB
= ( 62 lb )
( 5 ft ) i − ( 30 ft ) j + ( 6 ft ) k
( 5 ft )2 + ( − 30 ft )2 + ( 6 ft )2
= (10 lb ) i − ( 60 lb ) j + (12 lb ) k
∴ R = − ( 51.058 lb ) i − ( 70.766 lb ) j + (12 lb ) k
MO
i
j
k
=
0
30
3 lb ⋅ ft
− 51.058 −70.766 12
= ( 572.30 lb ⋅ ft ) i − (153.17 lb ⋅ ft ) j + (1531.74 lb ⋅ ft ) k
M O = ( 572 lb ⋅ ft ) i − (153.2 lb ⋅ ft ) j + (1532 lb ⋅ ft ) k W
.
COSMOS Chapter 3 Solution 23
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