University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

368

Pages:

1
Author:

Apolenajz

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 40. (a) By definition λ BC ⋅ λ EG = (1) (1) cosθ where λ BC = = λ EG = = Therefore ( 32 ft ) i − ( 9 ft ) j − ( 24 ft ) k ( 32 )2 + ( − 9 )2 + ( − 24 )2 ft 1 ( 32i − 9 j − 24k ) 41 (16 ft ) i − (12 ft ) j + ( 9.75) k (16 )2 + ( −12 )2 + ( 9.75)2 ft 1 (16i − 12 j + 9.75k ) 22.25 ( 32i − 9 j − 24k ) ⋅ (16i − 12 j + 9.75k ) 41 22.25 = cosθ ( 32 )(16 ) + ( −9 )( −12 ) + ( −24 )( 9.75) = ( 41)( 22.25) cosθ cosθ = 0.42313 or (b) By definition (TEG )BC θ = 65.0° W = (TEG ) cosθ = (178 lb )( 0.42313) = 75.317 lb or (TEG ) BC = 75.3 lb W .

COSMOS Chapter 3 Solution 40

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