University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2022
Views:

314

Pages:

2
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 98. (a) a : ΣFy : Ra = − 400 N − 600 N or R a = 1000 N ΣM B : M a = ( 2 kN ⋅ m ) + ( 2 kN ⋅ m ) + ( 5 m )( 400 N ) or M a = 6.00 kN ⋅ m b : ΣFy : Rb = −1200 N + 200 N or R b = 1000 N ΣM B : M b = ( 0.6 kN ⋅ m ) + ( 5 m )(1200 N ) or M b = 6.60 kN ⋅ m c : ΣFy : Rc = 200 N − 1200 N or R c = 1000 N ΣM B : M c = − ( 4 kN ⋅ m ) − (1.6 kN ⋅ m ) − ( 5 m )( 200 N ) or M c = 6.60 kN ⋅ m d : ΣFy : Rd = − 800 N − 200 N or R d = 1000 N ΣM B : M d = − (1.6 kN ⋅ m ) + ( 4.2 kN ⋅ m ) + ( 5 m )( 800 N ) or M d = 6.60 kN ⋅ m continued . COSMOS: Complete Online Solutions Manual Organization System e : ΣFy : Re = − 500 N − 400 N or R e = 900 N ΣM B : M e = ( 3.8 kN ⋅ m ) + ( 0.3 kN ⋅ m ) + ( 5 m )( 500 N ) or M e = 6.60 kN ⋅ m f : ΣFy : R f = 400 N − 1400 N or R f = 1000 N ΣM B : M f = ( 8.6 kN ⋅ m ) − ( 0.8 kN ⋅ m ) − ( 5 m )( 400 N ) or M f = 5.80 kN ⋅ m g : ΣFy : Rg = −1200 N + 300 N or R g = 900 N ΣM B : M g = ( 0.3 kN ⋅ m ) + ( 0.3 kN ⋅ m ) + ( 5 m )(1200 N ) or M g = 6.60 kN ⋅ m h : ΣFy : Rh = − 250 N − 750 N or R h = 1000 N ΣM B : M h = − ( 0.65 kN ⋅ m ) + ( 6 kN ⋅ m ) + ( 5 m )( 250 N ) or M h = 6.60 kN ⋅ m (b) The equivalent loadings are (b), (d), (h) .

COSMOS Chapter 3 Solution 98

of 2

Description

Free up your schedule!

Take 5 seconds to unlock