COSMOS Chapter 6 Solution 86 | Michigan State University

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

382

Pages:

1
Author:

omiliar74be

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 86. (a) FBD AC: Note: CE is a two-force member ΣM A = 0:  1   1  − ( 8 in.)  FCE  − ( 2 in.)  FCE  + 192 lb ⋅ in. = 0  2   2  E x = 19.20 lb FCE = 19.2 2 lb, E y = 19.20 lb (b) FBD CE: ΣFx = 0: Ax − 19.2 lb = 0, ΣFy = 0: Ay − 19.2 lb = 0, A x = 19.20 lb A y = 19.20 lb ! ! ! ! Note: AC is a two-force member ΣM E = 0: 4  1  FAE + FAE  + 192 lb ⋅ in. = 0 17  17  ( 3 in.)  FAE = −12.8 17 lb, Ax = 4 FAE , 17 Ay = 1 FAE , 17 ΣFx = 0: Ex − 51.2 lb = 0, ΣFy = 0: E y − 12.80 lb = 0, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. A x = 51.2 lb A y = 12.80 lb E x = 51.2 lb E y = 12.80 lb ! ! ! !