COSMOS: Complete Online Solutions Manual Organization System
Chapter 4, Solution 55.
Free-Body Diagram:
Using W = mg :
(a)
P( R cosθ + R cosθ ) − mg ( R sin θ ) = 0
ΣM C = 0:
2P = mg tan θ
tan θ =
(b)
2P
mg
or
2P
mg
θ = tan −1
With m = 0.7 kg and P = 3 N:
2(3 N)
2
(0.7 kg)(9.81 m/s )
θ = tan −1
= 41.145°
or
θ = 41.1°
COSMOS Chapter 4 Solution 55
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