University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

239

Pages:

1
Author:

FrextWhestembki

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 131. FBD BD: θ = 90° − 25° = 65° ΣM B = 0:  2 ( 0.2 m ) cos 25° D sin 65° −15 N ⋅ m = 0 D = 45.654 N FBD AC: ΣM A = 0: M A = ( 0.2 m )( 45.654 N ) = 0 M A = 9.13 N ⋅ m Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. !