University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

334

Pages:

1
Author:

Ciullismr

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 5. Free-Body Diagram: a1 = ( 20 in.) sin α − ( 8 in.) cos α a2 = ( 32 in.) cos α − ( 20 in.) sin α b = ( 64 in.) cos α From free-body diagram of hand truck ΣM B = 0: P ( b ) − W ( a2 ) + W ( a1 ) = 0 (1) ΣFy = 0: P − 2w + 2B = 0 (2) α = 35° For a1 = 20sin 35° − 8cos 35° = 4.9183 in. a2 = 32 cos 35° − 20sin 35° = 14.7413 in. b = 64cos 35° = 52.426 in. (a) From Equation (1) P ( 52.426 in.) − 80 lb (14.7413 in.) + 80 lb ( 4.9183 in.) = 0 ∴ P = 14.9896 lb (b) or P = 14.99 lb From Equation (2) 14.9896 lb − 2 ( 80 lb ) + 2 B = 0 ∴ B = 72.505 lb or B = 72.5 lb