University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

84

Pages:

1
Author:

Tyshawn Shaffer

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 29. FBD table + child: ( ) = 16 kg ( 9.81 m/s ) = 156.96 N WC = 18 kg 9.81 m/s 2 = 176.58 N WT 2 (a) Impending tipping about E , N F = FF = 0, and ΣM E = 0: ( 0.05 m )(176.58 N ) − ( 0.4 m )(156.96 N ) + ( 0.5 m ) P cosθ − ( 0.7 m ) P sin θ =0 33cosθ − 46.2sin θ = 53.955 Solving numerically θ = −36.3° and θ = −72.6° −72.6° ≤ θ ≤ −36.3° Therefore Impending tipping about F is not possible (b) For impending slip: FE = µ s N E = 0.2 N E ΣFx = 0: FE + FF − P cosθ = 0 or FF = µ s N F = 0.2 N F 0.2 ( N E + N F ) = ( 66 N ) cos θ ΣFy = 0: N E + N F − 176.58 N − 156.96 N − P sin θ = 0 N E + N F = ( 66sin θ + 333.54 ) N So Solving numerically, 330 cosθ = 66sin θ + 333.54 θ = −3.66° and θ = −18.96° Therefore, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. −18.96° ≤ θ ≤ −3.66°

COSMOS Chapter 8 Solution 29

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