COSMOS: Complete Online Solutions Manual Organization System
Chapter 4, Solution 155.
Free-Body Diagram:
From free-body diagram of frame with T = 300 lb
5
ΣFx = 0: C x − 100 lb + 300 lb = 0
13
∴ C x = −15.3846 lb
or
C x = 15.3846 lb
12
ΣFy = 0: C y − 180 lb − 300 lb = 0
13
∴ C y = 456.92 lb
Then
and
C =
or
C y = 456.92 lb
(15.3846 )2 + ( 456.92 )2
C x2 + C y2 =
= 457.18 lb
Cy
−1 456.92
= tan
= −88.072°
−15.3846
Cx
θ = tan −1
or C = 457 lb
88.1°
12
ΣM C = 0: M C + (180 lb )( 20 in.) + (100 lb )(16 in.) − 300 lb (16 in.) = 0
13
∴ M C = −769.23 lb ⋅ in.
or M C = 769 lb ⋅ in.
COSMOS Chapter 4 Solution 155
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