University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

126

Pages:

1
Author:

Dixie Summers

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 66. FBD Truss: ΣFx = 0: ΣM C = 0: Cx = 0 (8 ft )( 6 kips ) − (8 ft )( 9 kips ) + (16 ft ) G y − ( 24 ft )(12 kips ) = 0 G y = 19.5 kips FBD Section ABC: ΣFy = 0: 19.5 kips + C y − 6 kips − 9 kips − 12 kips = 0 C y = 7.5 kips Since only BE can provide the downward force necessary for equilibrium, it must be in tension, so CD is slack, FCD = 0 ΣFy = 0: − 6 kips + 7.5 kips − 3 FBE = 0 5 FBE = 2.50 kips T ! FBD Section FGH: Since only EF can provide the downward force necessary for equilibrium, it must be in tension, so DG is slack, FDG = 0 ΣFy = 0: 19.5 kips − 12 kips − 3 FEF = 0 5 FEF = 12.00 kips T ! Knowing that FCD = FDG = 0, inspection of joint D gives FDE = 0 ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS Chapter 6 Solution 66

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