University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

408

Pages:

2
Author:

pravitate8aj13

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 26. R ( ( 3π 3π 2 rdr = R2 − R12 2 4 ( ) ( ) Then R2 = Rm + kO2 = t )( ( 1 ( R1 + R2 ) 2 Rm = For ) ) 3π 4 R2 − R14 R22 + R12 R22 − R12 J 1 2 2 O 8 kO = = = = R2 + R12 2 2 3π 2 A 2 2 2 R − R 2 1 R2 − R1 4 Now And ( A = ∫ dA = ∫R 2 1 And Then 3π 4 R2 − R14 8 JO = (a) From Problem 9.25 R1 = Rm − and 2 1  t t   Rm +  +  Rm −  2  2 2  R1, R2 kO2 ( t 2 2 1  = Rm2 + t 2 4  Rm2 kO Or (b) Have ) t = R −R and t 2 ) ) R − kO % error = m × 100% = kO 1− 1+ = Rm2 + Rm − Rm2 + 1 t    4  Rm  1 t  1+   4  Rm  2 Rm 1 2 t 4 × 100% 1 2 t 4 2 × 100% continued COSMOS: Complete Online Solutions Manual Organization System Then t = 1: % error = Rm 1− 1+ 1+ 1 4 1 4 × 100% or % error = −10.56% t 1 = : % error = Rm 4 1− 1+ 11   44 11 1+   4 4 2 × 100% 2 or % error = −0.772% t 1 = : % error = Rm 16 1 1  1− 1+   4  16  1+ 1 1    4  16  2 2 × 100% or % error = −0.0488%

COSMOS Chapter 9 Solution 26

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