University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

222

Pages:

1
Author:

omiliar74be

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 3. FBD Block: Tension in cord is equal to P = 40 N, from FBD of pulley. ( ) W = (10 kg ) 9.81 m/s 2 = 98.1 N ΣF y = 0 : N − (98.1 N ) cos 20° + (40 N ) sin 20° = 0 N = 78.503 N Fmax = µ s N = ( 0.30 )( 78.503 N ) = 23.551 N For equilibrium: ΣFx = 0: ( 40 N ) cos 20° − ( 98.1 N ) sin 20° − F = 0 Feq = 4.0355 N < Fmax , F = Feq Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. ∴ Equilibrium exists F = 4.04 N 20°

COSMOS Chapter 8 Solution 3

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