University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

15

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 134. Have dB = (a) and 4 − d A = ( 0.33333 − d A ) ft 12 I AA′ = I GG′ + md A2 I BB′ = I GG′ + md B2 Then ( I BB′ − I AA′ = m d B2 − d A2 ) 2 = m ( 0.33333 − d A ) − d A2    = m ( 0.11111 − 0.66666d A ) Then (1.26 − 0.6 ) × 10−3 lb ⋅ ft ⋅ s2 = or 0.40 lb ( 0.11111 − 0.66666d A ) ft 2 32.2 ft/s 2 d A = 0.08697 ft d A = 1.044 in. or I AA′ = I GG′ + md A2 (b) or I GG′ = 0.6 × 10−3 lb ⋅ ft ⋅ s 2 − 0.4 lb 2 0.08697 ft ) 2( 32.2 ft /s = 0.50604 × 10−3 lb ⋅ ft ⋅ s 2 Then 2 kGG ′ = I GG′ 0.50604 × 10−3 lb ⋅ ft ⋅ s 2 = 0.4 lb m 32.2 ft/s 2 = 0.04074 ft 2 kGG′ = 0.20183 ft = 2.4219 in. or kGG′ = 2.42 in.

COSMOS Chapter 9 Solution 134

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