University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
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472

Pages:

1
Author:

Tarime9wn

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 47. FBD Truss: ΣFx = 0: By symmetry, Ax = 0 A y = M y = 8.5 kN FBD Section IMNJ: ΣM J = 0: ( 2 m )(8.5 kN − 1.5 kN ) − (1 m )(1.5 kN ) − ( 0.5 m ) 40 FGI = 0 41 FGI = 25.625 kN, ΣM G = 0: FGI = 25.6 kN T W ( 3 m )(8.5 kN − 1.5 kN ) − ( 2 m )(1.5 kN ) 40 FHJ = 0 41 FHJ = 30.8 kN C W − (1 m )( 3 kN ) − ( 0.5 m ) FHJ = 30.75 kN, ΣFx = 0: 40 ( 30.75 kN − 25.625 kN ) − 41 40 FGJ = 0 2441 FGJ = 6.18 kN T W Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS Chapter 6 Solution 47

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