University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2023
Views:

238

Pages:

1
Author:

imophulebf11

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 107. FBD motor and mount: Impending belt slip: cw rotation T2 = T1e µs β = T1e0.40π = 3.5136 T1 ΣM D = 0: (12 in.)(175 lb ) − ( 7 in.) T2 − (13 in.) T1 = 0 2100 lb = ( 7 in.)( 3.5136 ) + 13 in. T1 T1 = 55.858 lb, T2 = 3.5136 T1 = 196.263 lb FBD drum at B: ΣM B = 0: M B − ( 3 in.)(196.263 lb − 55.858 lb ) = 0 M B = 421 lb ⋅ in. r = 3 in. (Compare to 857 lb ⋅ in. using V-belt, Problem 8.130) Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS Chapter 8 Solution 107

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