COSMOS: Complete Online Solutions Manual Organization System
Chapter 9, Solution 28.
y =
By observation
b
y
2h
x=
or
b
dA = xdy =
2h
Now
dI x = y 2dA =
Then
I x = ∫ dI x = 2∫ 0
h
b 3
y dy
2h
1 3
bh
4
=
0
y =
From above
Now
h
y dy
b 3
y dy
2h
And
b y4
=
h 4
h
x
b
2
2h
x
b
2h
dA = ( h − y ) dx = h −
x dx
b
=
h
( b − 2 x ) dx
b
And
dI y = x 2dA = x 2
Then
I y = ∫ dI y = 2∫ 02
b
h
( b − 2 x ) dx
b
h 2
x ( b − 2 x ) dx
b
b
h 1
1 2
= 2 bx3 − x 4
b 3
2 0
3
4
h b b
1b
1 3
=2 − =
bh
b 3 2
2 2 48
continued COSMOS: Complete Online Solutions Manual Organization System
Now
JO = I x + I y =
1 3
1 3
bh +
bh
4
48
or J O =
And
bh
12h 2 + b 2
J
1
2
48
O
kO =
12h 2 + b 2
=
=
1
A
24
bh
2
(
)
(
bh
12h 2 + b 2
48
(
)
)
or kO =
12h 2 + b 2
24
COSMOS Chapter 9 Solution 28
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