University:
Mississippi College
Course:
CHE 141 | General Chemistry I
Academic year:

2022
Views:

370

Pages:

2
Author:

Abby D.

6.2 Law of Sines e CosinesBabsincCArea doesn't changeAcbsinA2b1 acsinBx22x2 absinc 7 2 1 cb sin A) = -acsinB) x2absinc = cbsin A =acsinBabcabcabcsinc = sin A = sinBDerived Law of sinesCablike g=mxtb- diff forms2.70=c760A6=3.67 SinA = SinB = sinc puse porportion you knowistab63°B 41°C4sin76° sin 630sin 76° sin419a44Cuse Given info instead of bsin 760 = 4sin639C5i076° = 4517419b-o already solved.sin76° Sin 76°Sin 76° sin760b= 4sin63°9 ExactC = 4sin410180-76-63-419Sin 769littlet sin 760acute=Cb2366'answerobtivecn 2.70Jacksin 100° sinBa75100%sin 100 - sin 35,3Ssin100°=7sinB7a57a= 7sin 35.3(sin') S Sin 100 = sinB (sin")sin 100180-4477135.37TO check forSin ((5sin 1009) = Bother anglesor if in radianssin (0,703)= Brad-rad=BX 44.7°(180) Law of CosinesnStart w/ law of sinesrr[srac law of cosinesthen tryLD can use bothC2 - a2tb - 2abcosc - for non right triangles610/Ba2= b2 2 + c2 - 2b0 COSAS=a52= 72+62-2(7)6) COS AGA25=49+36-84 COSA, (84x(ex)) not equalCOS-157sb25 - 85 - 84 COSA7-85-85ba=az+c2-2accosB-60=-84 COSAC2-02+62-2010COSC-84-84-inverse(COS')S = COSA (cos-')7cos-'s = A7