University:
Missouri State University
Course:
MTH 103 | Intermediate Algebra
Academic year:

2020
Views:

201

Pages:

2
Author:

Patricia West

Kuta Software - Infinite Algebra 1 Factoring Trinomials (a > 1) Factor each completely. 1) 3p ^ 2 - 2p - 5 - 15p ^ 2 -5p|^ 3 p 3p ^ 2 + 3p - 5p - 5 3p(p + 1) - 5(f + 1) (p + 1)(3p - 5) Name Key Date Day 9 Period 2) 2n ^ 2 + 3n - 9 -18x)^ 2 lon |-3x) 2n ^ 2 + 6v - 3n - 9 2n(n + 3) - 3(n + 3) (2n - 3)(n + 3) 3) 3n ^ 2 - 8n + 4 12n ^ 2 -|rr)|-2n 3v ^ 2 - 6w - 2n + 4 3m(n - 2) - 2(m - 2) 2(n - 2)(n - 2) 5) 2v ^ 2 + 11v + 5 I odot u ^ 2 10 u|V 2v ^ 2 + 10v + v + 5 2v(v + 5) + 1(v + 5) 2v + 1 )(v+5) 4) 5n ^ 2 + 19n + 12 (60n ^ 2)/(4n115n) 5n ^ 1 + 15n + 4 / n + 12 5n(n + 3) + 4(n + 3) ( 5n + 4x(n + 2) 6) 2n ^ 2 + 5n + 2 4n ^ 2 4nln 2n ^ 7 + 41m + n + 2 2n(n + 2) + 1(n + 1) ( 2v(v + 1)(v + 1) 7) 7a ^ 2 + 53a + 28 (194a ^ 2)/(4a / 490) 7a ^ 2 + 4a + 4/9 * a + 28 a(7a + 4) + 7(7a + 4) (7a + u)(o + 1) 8) 9k ^ 2 + 66k + 21 3(3k ^ 2 + 22k + 7) (21k ^ 2)/(2|1k| * k) 3(3k ^ 2 + 21k + k + 7) 3[ underline 3k ( underline x+7) - (x + 7) ] 3(3k + 1)(k + 7) 9) 15n ^ 2 - 27n - 6 (- 10r * e ^ 2)/(- 10r / n) 3(5n ^ 2 - 9n - 2) 3(5n ^ 2 - 10n + n - 2) 3(5n(n - 2) + 1(n - 2)) 3(n - 2)(5n + 1) 11) 4n ^ 2 - 15n - 25 - 100n ^ 2 -20n|5n 4n ^ 7 - 20n + 5k - 25 4n(n - 5) + 5(n - 5) (4n + 5)(n - 5) 13) 4n ^ 2 - 17n + 4 - | 6111 - lfloor infty n rfloor-1 rceil 4n ^ 2 - 16n + n + 4 L( n(n - 4) - (n - 4) (4m - 1)(n - 4) 15) 6x ^ 2 + 37x + 6 (36x ^ 2)/(36x1x) 6x ^ 2 + 36x + x + 6 6x(x + 6) + 1(x + 6) 6x + 1 )(x+6) 17) 6n ^ 2 + 5n - 6 -3672 an 1-4n 6n ^ 2 + 9n - 11n - 6n 3n(2vo + 3) - 2(2n + 3) 3n-2) (2n + 3) 10) 5x ^ 2 - 18x + 9 4 / (x ^ 2) - boxed 15x |-3x 5x ^ 2 - 15x - 3x + 9 5x(x - 3) * 3(x - 3) (5x - 3)(x - 3) 12) 4x ^ 2 - 35x + 49 196x ^ 2 -7x|-28 x. 4x ^ 2 - 7x - 7.8x + 49 x(11x - 7) - 7(4x - 7) (x - 7)(4x - 7) 14) 6x ^ 2 + 7x - 49 6x ^ 2 + 21x - 14x - 49 ^ 2 3x(2x + 7) - 7(2x + 7) (3x - 7)(7x + 7) -2941 21x ]-141x 16) - 6a ^ 2 - 25a - 25 - (6a ^ 2 + 25a + 25) - (10a ^ 2 + 10a + 15a + 25) - [2a(3a + 5) + 5(3a + 5)] (2a + 5)(3a + 5) (150alpha ^ 2)/(10a115alpha) 18) 16b ^ 2 + 60b - 100 4(4b ^ 2 + 15b - 25) 4(4b ^ 2 + 20b - 5b - 25) 4[4b(b + 5) - 5(w + 5)] 4(4b - 5)(b * 5) (- 100b ^ 2)/(2001 - 5b)