University:
Missouri State University
Course:
MTH 103 | Intermediate Algebra
Academic year:

2019
Views:

371

Pages:

2
Author:

Pompanin8za

No WORK NO CREDIT Algebra 1 Name: K e y ^ * Unit 10: PQ 1 Date: Period: "PRACTICE" QUIZ 1... Simplifying Radicals and Radical Operations Part 1: Simplify the radical completely. No decimal answers. 4sqrt(3) 1) sqrt(48) = sqrt(46) * sqrt(3) = 4sqrt(3) 6sqrt(3) 2) sqrt(108) = sqrt(36) * sqrt(3) = 6sqrt(3) - 3/4 * sqrt(2) 3) - 1/4 * sqrt(18) - 1/4 * sqrt(9) + sqrt(2) = - 1/4 + 3sqrt(2) = - 3/4 * sqrt(2) Part 2: Simplify the radical expression by adding and subtracting. No decimal answers. - 12sqrt(13) 4) - 6sqrt(13) - 6sqrt(13) = - 12sqrt(13) - 37sqrt(3) + 18sqrt(2) ) matrix -4 sqrt 3 +6 sqrt 15-11 sqrt 2 & sqrt 3 &-4 sqrt 3 +11* sqrt 9 &-4 sqrt 3 +1 sqrt 2 -33 sqrt 3 \\ 4sqrt(3) + 6 + 3sqrt(2) - 11 * 3sqrt(3) &1&1&1&1&1&1&1\\ -37 sqrt 3 +18 sqrt 2 matrix Part 3: Simplify the radical 10sqrt(3) 6) sqrt(10) * sqrt(30) = sqrt(300) = sqrt(100) * sqrt(3) = 10sqrt(3) 2 7) 1/7 * sqrt(98) * sqrt(2) = 1/7 * sqrt(196) = 1 7 *^ 14 = 14 7 =2 12sqrt(2) - 4sqrt(6) ) sqrt(3) * (4sqrt(6) - 2sqrt(8)) = 4sqrt(17) - 2sqrt(24) = 4sqrt(9) * sqrt(2) - 2sqrt(7) * sqrt(6) = 4 * 3sqrt(2) - 2 * 2sqrt(6) = 12sqrt(2) - 4sqrt(6) 9) ( sqrt(5) - 2(sqrt(5) + 2) = sqrt(25) + 2sqrt(5) - 2sqrt(5) 5 - 4 = 1 Part 4: Simplify the radical expression by dividing. No decimal answers. 2sqrt(6) 10) sqrt(480/20) = sqrt(24) = sqrt(4) * sqrt(6) = 2sqrt(6) (3sqrt(5))/5 - 9/(3sqrt(5)) * (sqrt(5))/(sqrt(5)) = (9sqrt(5))/(3sqrt(25)) = (9sqrt(5))/(3 * 5) = (9sqrt(5))/15 = (3sqrt(5))/5 11) Part 5: Simplify the radical expression by performing the given operation. No decimal answers. 384 12) (8sqrt(6)) ^ 2 = (gamma * sqrt(6))(7sqrt(6)) = 64sqrt(36) = 64 * 6 = 384 3sqrt(2) - 3sqrt(11) 13) 3 sqrt 2 - 3sqrt(11) * NoTL * 3kerTe .z mu s 855 14) sqrt(320) = sqrt(64) * sqrt(5) = sqrt(5) 15) sqrt(75) - 5sqrt(3) = sqrt(25) * sqrt(3) - 5sqrt(3) = 5sqrt(3) - 5sqrt(3) = 0 Part 6: Applications. A = 45/2 * sqrt(3) + 45 16) Find the area of the triangle to the right. Keep your answer in exact radical form (no decimals). A = plus/minus b * h A=1553+45 2 sqrt(25) * sqrt(3) + 10 5sqrt(3) + 10 sqrt(75) + 10 A=(9) (5√3+10) A = 1/2 * (45sqrt(3) + 9c) 3.14 SEC. 17) sqrt(25/sigma + 4) 5 + 4 < 9 The time that a pendulum of a grandfather clock takes to swing forth one cycle is the period of the pendulum. The formula for finding the period Tin seconds is T = 2pi * sqrt(L/32) where L is the length of the pendulum in feet. T = calculator for this entire problem to find the period of a that is L = 8 long. Round your final answer to the nearest hundredth. ( pi = 3.14 ) T = 2pi * sqrt(5/32) = 2pi * sqrt(1/4) = 2pi * 1/2 = pi Part 7: Multiple-Choice. Choose the best answer. C18) When x = 3 which expression can be completely simplified to 6sqrt(5) ? A) 12sqrt(5x) B) 2sqrt(3x) aligned 2 sqrt 15x \\ 2sqrt(45) =2 sqrt 9, aligned ) 3sqrt(5x) C19) The value of r is a real number such that 0.4 <= r <= sqrt(0.5) possible values of r? sqrt(5) = 2 * 3sqrt(5) = 6sqrt(5) 0a ^ 4 <= r <= 0 r approx0.s A) sqrt(t ^ - 6) = 0.25 B) r * sqrt(r ^ 2) * 40, 25 3sqrt(r) = 2, 1 D) r ^ 3 * sqrt(r) = 0.09 A 20) Simplify: 4*(4 sqrt 18 )^ *1 = 4/(4sqrt(18)) = 1/(sqrt(9) * sqrt(2)) = 1/(3sqrt(2)) * 12/(sqrt(2)) = (sqrt(2))/(3 * 2) = (sqrt(2))/6 A) (sqrt(2))/6 B) (sqrt(2))/12 C) (sqrt(2))/96 D) 48sqrt(2) A