University:
Missouri State University
Course:
MTH 103 | Intermediate Algebra
Academic year:

2019
Views:

486

Pages:

5
Author:

Hugh Kaufman

Name: KEY Block: Date: Unit 0: Algebra | Review Review Sheet Solve the following equations for x. Show all work! 1) 1/5 * x - 4(2x + 3) = 12 1/5 * x - 8x - 12 = 12 (1/2 * x - 8x = 24) * 5 x - 40x = 120 - 39x = 120 x = - 40/13 2) 2(2x + 3) - x = - 4(5x + 1) \\ 4x+6-x=-70x-4 4x + 6 - x = - 20x - 4 3x + 6 = - 20x - 4 10 = - 23x x = - 10/23 ) 3) |6x + 10| - 2 = 10 |6x + 10| = 12 4)=4x-3=8 14x-3=28 6x + 10 = 12 6x = 2 x = 1/3 6x + 10 = - 12 6x = - 22 x = - 11/3 4x - 3 = 28 4 = 31 x = 31/4 4x - 3 = - 28 4x = - 25 x = - 25/4 Solve the following inequalities for Xx Show all work! Graph the solution of each thequality on line provided. 5) 7x - 5 <= - 2x + 6 9x = 11 x <= w / 4 6) 7x - 14 > 21 (7 * 235)/7 x > 5 n/q 5 7 |4/5 * (- 3/10)| < - 5 No Solution 4 (5 x- 3 10 L-5) 6(4/5 * x - 3/40 * 5) 8x - 3 < - 56 8 * (- 47) \\ *--4\% 8 * (- 3) * 56 3/8 A*y_{s} Valx^ negative s(2 < 3/2 * (2x - 8) <= 8) * 2/3 (4/3 < 2x - 8 < 16/3) * 3 4 < 6x - 24 <= 16 28 < 6x < 40 14/3 < x < 20/3 14/3 26/3 9) ((-3,3), (1,1), (4,-2), (3,1), (5,6), (-4,2)) 10) ((4,2), (-3,1), (2,4), (-3,2), (5,6), (7,2), (-2,6), (0,7), (3,5)) Range: -3,1,4,3,5,-4 3, 1, - 2, 6, 2 Domain: Domain: (4, - 3, 2, 5, 7, - 2, 0, 5)/(2, 1, 4, 6, 7, 5) Range: Function or Relation Function or Relation Reasoning No repeasing Reasoning Repeating X-valves 11) Evaluate at the given value. a) f(x) = x ^ 2 - 10; f(3) F(3)=32-109-10-1 b) f(x) = - 2x + 6x + 3; f(- 4) F(- 4) = - 2(- 4) + 6(- 4) + 3 = 8 - 24 + 3 =(-13 c) f(x) = 2/3 * x + 6; f(- 4) f(- 4) = 2/3 * (- 4) + 6 = - 8/3 + 6 =( 10 3 Graph the following equations and inequalities. Don't forget to shade for inequalities! 3x + 5y = 15 5y = - 3x + 15 y = - 3/3 * x + 3 13. y = 3 14. y = 2/3 * x - 2 15). x>-2 6r - 2 16) f(x) >= - 2/3 * x - 1 O >= - 1 17) 3x + y <= 6 y <= 6 - 3v Use the information below to write the equation of the line with the given characteristics. 18) The line parallel to f(x) = 1/3 * x - 5 and contains the point (2,1) m = 1/3 1 = 1/3 * (2) + b 1 = 2/3 + b 1/3 = b y = 1/3 * x + 1/3 19) The line that passes through the points (2,-4) and (2,6) 6-(-4) M=2-2 10 undefined X = 2 20) The line with a slope of -4 through the point (3,7) 7=-4(3)ウ 7 = - 12 + b 19 = b y = - 4x + 19 m = 1/2 21) The line perpendicular to the line y = - 2x + 5 and contains the point (3,5) 5 = 1/2 * (3) + 5 S = 3/2 * rb 7/2 = b y = 1/2 * x + 7/2 22) The line with a slope of 2 and a y-intercept of -4.5 y = 2x - 4.5