University:
Missouri State University
Course:
MTH 136 | Precalculus 1
Academic year:

2019
Views:

79

Pages:

2
Author:

Bruno Manning

Calculus Trig Review Worksheet Name Key Without a calculator, evaluate each trig function at the given angle: 1. cos((7pi)/6) - (sqrt(3))/2 2. csc((2pi)/3) (2sqrt(3))/3 3. tan((3pi)/4) -1 sin((3pi)/2) 5. cos 240 deg 6. cot 2pi (13) (01) अर्थ - 1/2 7. cos((- 2pi)/3) 1/2 8. sin((11pi)/6) 2 9. sec((5pi)/4) - sqrt(2) 10. tan(- pi) 11. csc(- 330 deg) 12. 6ot * (4pi)/3 (0) odot 1 = 0 2 (sqrt(3))/3 Without a calculator, solve for each angle(s) that makes the given equation true on the interval [0,2]. 13. sin theta = (sqrt(2))/2 B = pi/4, 30/4 14. cos theta = - (sqrt(3))/2 50 20 15. sec(theta) = sqrt(2) sigma = (I*pi)/(4pi) = (In)/4 16. \mathfrak{c}*sc*theta = - 1 S (e 2 emptyset:-1 \langlex - 1\rangle d = (3pi)/2 17. tan theta = - (sqrt(3))/3 \mathcal{H} = (EM)/L_{sigma} (11pi)/(le) 18. cot theta = emptyset phi =0.m,2 pi Use a calculator to find each value: (round to 3 decimal places if necessary) 19. sin 81° 988 20. tan - 135 deg 21. cos((4pi)/9) 22. sec(- 270 deg) undefined 23. cot (3pi)/4 24. cot 90° Verify each of the following identities: 25. cos^3 theta + sin^2 theta * cos theta = cos theta 3theta(ro * s ^ 2 * theta + sin^2 theta) = raj*theta 2000 (1)= COSO cos theta = cos theta 26. (sec^2 theta - 1)/(tan theta) = tan theta (tan^2 a * 3)/(tan delta) = tan alpha*beta tan theta = tan theta 7 * (1 + tan theta) ^ 2 = sec^2 theta + 2tan theta (i*pi*tan*delta)(i*pi * tan delta) = sec^2 delta + Z*pi*an*theta =zran theta*r + an*theta =serc^ 2 theta+2 tan theta sec(x) * 3 = 2con*theta = sec^2 theta + 2cos theta . (1 - 2cot theta)/(cot theta) = tan theta - 2sec(theta) 28 1/(cot g) = (2cot g)/(cot g) = cot g - 2.5cg Tan*theta = 2/(sin theta) * (sin theta)/(cos theta) = r * sin theta - 2.5theta*C*theta tan theta = 2/(6.23 * 0) = 78.6 * 0.8 - 2.38 < 0 tan theta - 2sec(theta) = tan theta - 2sec(theta) 29. csc^4 theta - cot^4 theta = 2csc^2 theta - 1 cot^ 2 theta-cot^ 2 theta) (csc^2 theta - cot^2 theta) = 2csc^2 theta - 1 (csc^2 theta + cot^2 theta) * C_{1} )=2csc^ 2 theta-1 csc^2 theta + (csc^2 theta - 1) = 2csc^2 theta - 1 2csc^2 theta - 1 = 2csc^2 theta - 1 30. (1 + sec(theta))/(tan theta + sin theta) = csc(theta) (1/(cos theta) * (cos theta + 1))/((l ^ 2)/(l ^ 2 * sin theta) * (sin theta + sin theta + sin theta)) = cos theta (cos theta + 1)/(sin theta * (1 + cos theta)) = csc(theta) 1/(sin 3) = csc(theta)