University:
Missouri State University
Course:
MTH 460 | College Geometry
Academic year:

2020
Views:

402

Pages:

2
Author:

grosikesf4

Name: Rey Date: Pythagorean Theorem Word Problems a ^ 2 + b ^ 2 = c ^ 2 1) To get from point A to point B you must avoid walking through a pond. To avoid the pond, you must walk 34 meters south and 41 meters east. To the nearest meter, how many meters would be saved if it were possible to walk through the pond? 34 m 41 m B 34 ^ 2 + 41 ^ 2 = c ^ 2 1( 56 + 1681 = c ^ 2 sqrt(283) * 1 = sqrt(c ^ 2) c \approx 53m 34+41-75 75 - 53 = 22m Shorter 2) A baseball diamond is a square with sides of 90 feet. What is the shortest distance, to the nearest tenth of a foot, between first base and third base? C 90ff 9oft 90 ^ 2 + 90 ^ 2 = c ^ 2 \$ 100 + 8100 = c ^ 2 sqrt(16, 200) = sqrt(c ^ 2) C \approx 127.3ft 3) Find the distance between the 2 points on the coordinate plane below. Y (7,8) C 6 ام 4 ^ 2 + b ^ 2 = c ^ 2 16 + 36 = c ^ 2 sqrt(52) = sqrt(c ^ 2) C ^ 7.2 (3,2) 44 A X 4) The diagonal of a TV is 40 inches and its width is 32 inches. Will the TV fit on a shelf that is 20 inches high? a 40 in 32 in b a ^ 2 + 32 ^ 2 = 40 ^ 2 a ^ 2 + 1024 = 1600 sqrt(a ^ 2) = sqrt(57) * 6 a = 24in It will not fit On a shelf that is 20 inches 5) How far up a wall will an 11 meter ladder reach, if the bottom of the ladder must be 4 meters from the base of the wall? Ilm b 4 ^ 2 + b ^ 2 = 11 ^ 2 16 + b ^ 2 = 121 \\ -16 aligned sqrt(b ^ 2) = sqrt(105) b = 10.2m 4m a 6) Two joggers run 8 miles north and then 5 miles west. What is the shortest distance, to the nearest tenth of a mile, they must travel to return to their starting point. 5 mi a C 8 mi b 5 ^ 2 + 8 ^ 2 = c ^ 2 25 + 64 = c ^ 2 sqrt(89) = sqrt(C ^ 2) C9.4 miles