Math Test Review Chapter 11 Key

Geometry CP Chapter 11 Test Review Name: Kay 1. 46 | | | 20 Shaded = 20 * 16 - π(15)² = 1058 - 224.97 ≈ 227.09 2. 40 | | | 24 A = 36 + 2π(12) A = 1784 + 72(2) A = 1784 + 144 A = 1928 3. 21 | | | 37 b₂ = 3 + 42 = 45 A = ½h(b₁ + b₂) A = ½(21)(37 + 45) A = 210 + 420 A = 630 4. 9 in. | | | 8 in. A = πr² + ½b(h) A = π(9)² + ½(16)(28) A = 324 + 224 A = 548 5. 26 | | | 21 A = 20² + 2π(20) A = 400 + 40π A ≈ 525.66 6. 14 | | | 23 b₂ = 37 + 23 = 60 A = ½h(b₁ + b₂) A = ½(20)(37 + 60) A = 527.85 7. 12 | | | 12 A = 12(40) + 12(40) A = 480 + 480 A = 960 8. 6 | | | 8 A = bh A = 6 * 8 A = 48 9. 8 m | | | 4 m d₁ = 12 d₂ = 8√5 + 8√5 = 16√5 A = ½d₁d₂ A = ½(12)(16√5) A = 32√5 ≈ 55.43 Find the unknown area. 10. A = 54 ft² 11. A = 85.75 mm² 12. Rectangles ABCD and EDGH are similar. The width of ABCD is 18 centimeters and the perimeter is 120 centimeters. The length of EFGH is 91 centimeters. Find the ratio of the areas   of triangle ABC to the area of triangle DEF. sides = 6/13 ratio of the areas = 36/169 13. Find the lengths of the bases of the trapezoid whose height is 5 meters. One base is three times as long as the other base. The area is 70 square meters.   70 = 1/2 * 5 * (x + 3x) bases: 7 and 21 The area of circle R is 295.52 square inches. The area of sector PRQ is 55 square inches. Find the indicated measure. 14. Radius of circle   R √(295.52 / π) = 9.7 inches 15. Circumference of circle R C = 2π * 9.7 C ≈ 60.9 inches 16. m∠PQ 55/295.52 = x/360 m∠PQ = 67° 17. Length of PQ y/60.9 = 67/360 length of PQ = 11.3 Find the exact area of the circle. 18. A = π(3/8)² A = 9π/64 in² 19. A = π(3.7)² A ≈ 13.69π ft² 20. The area of a circle is 654 square centimeters. Find the diameter. A = πr² 654 = πr² r ≈ 14.1 cm d = 28.2 cm Find the areas of the sectors formed by ∠ACB. (Find the area of the shaded and unshaded arcs) 21. Shaded: x/π8² = 60/360 x = 33.5 Unshaded: y/π8² = 300/360 y = 167.6 22. Shaded: x/π12.8² = 110/360 x = 157.3 Unshaded: y/π12.8² = 250/360 y = 357.4 Use the diagram to find the indicated measure. 23. Find the area of ⊙M. Shaded A = 223.9 24. Find the radius of ⊙M. A = πr² 84.14 = πr² r = 5.2 m 25. Find the diameter of ⊙M. A = πr² 72.39 = πr² r = 4.8 m d = 9.6 m The area of circle V is 624.36 square meters. The area of sector SVT is 64.17 square meters. Find the indicated measure. 26. Radius of circle V 624.36 = πr² r = 14.1 m 27. Circumference of circle V C = 2πr C = 2π(14.1) = 88.6 28. m∠ST 64.17/624.36 = x/360 m∠ST = 37° 29. Length of ST y/88.6 = 37/360 y = 9.1 m 30. Perimeter of shaded region 14.1 + 9.1 + 14.1 = 37.3 31. Perimeter of unshaded region SRT = 88.6 + 9.1 = 79.5 42. A = 1/2 * a * P A = 1/2 * 9 * (59.68) A = 268.56 43. A regular polygon has an angle measure of 20° and a side measure of 6 cm. What is the area of the polygon? A = 1/2 * a * P A = 1/2 * 17.01 * (6 * 18) A = 918.54 Find the probability that a point K, selected randomly on AE, is on the given segment. Express your answer as a fraction, decimal, and percent. 44. AC 5/32 = 0.15625 = 15.625% 45. BD 20/32 = 5/8 = 0.625 = 62.5% 46. CE 12/32 = 3/8 = 0.375 = 37.5% 47. AD 24/32 = 3/4 = 0.75 = 75% Find the probability that a randomly chosen point in the figure lies in the shaded region. 48. Circle: π(13)² = 169π Shaded: 169π - 2(10π) = 149π P = 149π / 169π ≈ 0.88 = 88% 49. Total: 16(16) = 256 Shaded: 128 - 2(20) = 88 P = 88/256 = 0.34375 = 34.375% 50. Hexagon: 1/2 * 3.5√3 * (6 * 7) = 73.5√3 Circle: π(3.5)² = 12.25π Shaded: 73.5√3 - 12.25π ≈ 26.63 P = 26.63 / 49π ≈ 0.173 = 17.3% 51. Total: 260 Shaded: 80 P = 80/260 = 0.3077 = 30.77%