University:
Swansea University
Course:
EG-086 | Engineering Science
Academic year:

2023
Views:

226

Pages:

3
Author:

Lloyd R.

Acceleration field will be at any gres point in the Euleres ferd al to the acceleraten of equal a fheid partick at a gives location (position) is the Eulenies flow field. Particle acceleration is Everios and Descimpios Lagrangios Steady, Ind Compressable flow onsider two dimensional, steady Covergin Prough the plane covaniya the figure Center マー chomed Shows 15 velocity on the horizontal (ithe (x-axis) + accelevation of a mis) goes by... find Jexpression for the particle moving along the conster as line using using (a) The Eulerias approach (b) The Lagranchian approach tagranchias Valuate the acceleration. When the particle is at the and ating end of the channel. beginning A - VI u-vi [+], v=0, W=0 o = ne (a) Eulerian descaption. Accel Acceleration 2- of +3.F df Ax = 2y + dou 아 ax = 0 ++ tw By 0 ax= V. [+][+] [[7]] [+1]= [六][+1]= =쁜[H즌] (x+1) uy y ln(1+). (b) The Lagro Lagronchian approach =[+] Now we dont have time ,50 dap dxp Udre Now integrating. [+1] ہے ماد Upan VIL V, dt Us de olf