University:
Swansea University
Course:
MA-252 | Probability Theory
Academic year:

2023
Views:

369

Pages:

3
Author:

Amal J.

Q.Solve the system of equation4xtay+8=14, = xtsy -3=10 Siedalxty +83 = 20 using GaussHeration method.Ans4x +2y+8 =x - sy -3 = 10x xty+ 83 = 20& - 314y= 'sl 10-x+323 = I [ 202fx-y]38First lterationput y=0, 3=0 this in eq1xx = 14 = 3.54109put x = 3.5, 3=0 in eg2years [10- 3'15] I les 1.3put x 3.5, y= 1.3 in eq38 03.3 1.3) = 1.911 Second iterationageput y= 1.3 13 = 1.9 in 1-eqIx +1 I 14 - 2X1-3 - 1-9]= 2.375stpsifput x 2-375, 3=109 ineq 229375 4'1-9=10/905put x2 2.375 1/83 y=11.908 8 in eql3= = I 8 { 20 - 2.375 - 1.9051)10.9(i)= 1-9653rd iterationput y= 1.905, 13 = 1.965 ineq1P.INE-IX 4 1 (14 - -02 X1.905 - 1.965]po 2 2.E=twlJ. 2.05625 // Putx=2.056 , of 1.965in eq2y10 - 2.056 + 1.965]=5[9.909]= 1.9818.Put x = 2.056, y= = 1.9818in eq 3z= 8 I [20 - 2.056 - 1.981]3= 1.995= 24th lteration60.0Put y= 1.9818, z= 1.995 in eq(1)youXI14-2x1-9818. - - 1.9954=$500.00