Dimensional Analysis: Using Actual Yield to Find Reactant Amount - Edubirdie

University:
University of Arkansas
Course:
CHEM 1123 | University Chemistry II
Academic year:

2019
Views:

250

Pages:

1
Author:

BobN

In this example, we use molarity as a conversion factor in dimensional analysis. Our problem reads, "What mass of sodium phosphate is needed to make an 875 milliliters of 1.3 molar sodium phosphate solution?" Our equation for molarity is moles of solute divided by liters of solution. As a conversion factor, we can say that one liter of solution has 1.3 moles of sodium phosphate. We'll start our dimensional analysis with 875 milliliters of sodium phosphate solution. We can convert from milliliters to liters of solution, then use the molarity of the solution to convert from liters of solution to moles of solute, sodium phosphate. Our last step is to convert from moles of sodium phosphate to grams of sodium phosphate using the molar mass. Completing our calculation, we should get 186 grams of sodium phosphate.

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