#2 Evaluate the Limit | Answer Key - Edubirdie

University:
University of Cambridge
Course:
0580 IGCSE | Mathematics
Academic year:

2023
Views:

478

Pages:

2
Author:

Shahbaz A.

Limit shahbaz ahmed August 2024 An important Limit: sin x =1 x−→0 x lim .................................... Evaluate the limit limx−→0 sin x◦ x limx−→0 sin x◦ x Solution Since πRadian = 180◦ ◦ 1Radian = [ 180 π ] 1 ◦ xRadian = [ 180 π x] = 180 ◦ π x Now limx−→0 sin x◦ sin x◦ = limx−→0 180 ◦ x π x π sin x◦ sin x◦ limx−→0 = [limx−→0 ] x 180 x◦ sin x◦ π π limx−→0 = ×1= x 180 180 2

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