University:
University of Cambridge
Course:
0580 IGCSE | Mathematics
Academic year:

2023
Views:

399

Pages:

2
Author:

Shahbaz A.

Q 61 Algebra Word Problems Packet No 1 shahbaz ahmed August 2024 Q 61.The difference between Jon’s age and Sue’s age is 18 years. If Jon is six years more than five times Sue’s age, how old is each person? Solution Let age of Sue= x years. Five times Sue’s age =5x years. Six years more than five times Sue’s age=5x+6 years. =⇒ Age of Jon= 5x+6 years. The difference between Jon’s age and Sue’s age= 5x+6- x=4x+6 years. The difference between Jon’s age and Sue’s age = 18 years. According to the condition. 4x + 6 = 18 1 4x + 6 − 6 = 18 − 6 4x = 12 x= 12 4 x = 3 years Age of Sue=3 years. Age of Jon= 5(3)+6=21 years. Age of Jon= 5(3)+6=21 years. Checking Age of Sue= 3 years. Five times Sue’s age =5(3) =15 years. Six years more than five times Sue’s age=15+6=21 years. =⇒ Age of Jon=21 years. The difference between Jon’s age and Sue’s age= 21-3=18 years. The given difference between Jon’s age and Sue’s age = 18 years. All conditions are satisfied 2