University:
Amherst College
Course:
CHEM 151 | Introductory Chemistry
Academic year:

2022
Views:

127

Pages:

3
Author:

Edwin Conner

Chemistry 11 – Discussion 9/27/10 Fall 2010 Titration Problem 1. 37.2 ml of 0.325 M HNO3 are titrated with 47.0 ml of 0.115 M Ba(OH) 2. a. Has the equivalence point been reached? b. What is the concentration of H+ ions in excess after the reaction goes to completion? c. What is the pH? d. How much more Ba(OH)2 must be added to reach the equivalence point? Chemistry 11 – Discussion 9/27/10 Fall 2010 Oxidation Numbers Rules for Assigning Oxidation Numbers (see also Zumdahl, Table 4.3 for these rules in a different format) 1. The oxidation number of an atom in pure elemental form (e.g., Zn, Cu, H2, O2) is 0. 2. The sum of the oxidation numbers of the atoms in any uncharged molecule or compound is 0. The sum of the oxidation numbers of the atoms in a charged species (such as a polyatomic ion) is equal to the charge of the species. 3. a. Within compounds, alkali metals have oxidation number +1 (e.g., NaCl). b. Within compounds, alkaline earth metals have oxidation number +2 (e.g., BaCl2). c. Within compounds, hydrogen (H) has oxidation number +1, except in compounds with alkali metals or alkaline earth metals. d. Within compounds, fluorine (F) has oxidation number –1. e. Within compounds, oxygen (O) has oxidation number –2, except in compounds with fluorine. f. Within compounds, the other halogens have oxidation number –1, except in compounds with fluorine or oxygen. http://chemlab.pc.maricopa.edu/periodic/printable.gif Chemistry 11 – Discussion 9/27/10 Fall 2010 1. Assign the oxidation state of each atom within the following compounds: a. Li3N b. NH3 c. N2H4 d. NO2 e. KNO3 f. BrF3 g. HOBr h. NaH 2. Identify whether the following balanced reactions are oxidation–reduction reactions. If so, identify which element is oxidized and which is reduced. Write the oxidation and reduction half reactions. a. 2 C2H6 (g) + 7 O2 (g)  4 CO2 (g) + 6 H2O (g) b. CuSO4 (aq) + Na2CO3 (aq)  CuCO3 (s) + Na2SO4 (aq) c. 2 CuCl (aq)  CuCl2 (aq) + Cu (s)

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