Chemistry 08
Spring 2010
Assignment 3 Solutions
From “Chemistry in Context” (E-reserve) Chapter 4: #7, 9, 10, 13, 25, 27, 41, 53.
1.20×107 kJ
7.
9. b. ΔH = -43 kJ/mol. The reaction is exothermic.
c. No, many of the C-H bonds stay in tact in the reaction, and they would appear on
both sides of the equation. Thus, they cancel out and can be omitted from the
calculation.
10. a. exothermic
b. endothermic
c. endothermic
d. exothermic
13. a. -106 kJ/mol, exothermic
b. -146 kJ/mol, exothermic
c. -1 kJ/mol, slightly exothermic
25.
Energy is never created or destroyed, so the total energy in the universe is
constant. However, the energy may not be in useful form. As we use energy to do
work and power our lives, we transform it from useful forms (e.g. fossil fuels) to
non-useful forms (heat, friction). Hence, there can be an energy crisis when there
is not enough energy readily available in useful forms.
27. a. The heats of combustion of octane and butane are 5450 kJ/mol and 2859 kJ/mol,
respectively. On a per mass basis, however, these are 47.8 kJ/g and 49.3 kJ/g.
Octane is a bigger molecule containing more atoms and more bonds, hence it has
a higher heat of combustion per molecule (or per mole). On a per gram basis,
however, the two are nearly equal. In fact, butane has a slightly higher heat of
combustion per gram. Mass is the important measure when transporting and
buying or selling energy sources, and this calculation shows there’s no great
advantage to large molecules over smaller ones.
b. There is a trend toward smaller heat of combustion per gram with increasing size
of the molecule, so we would expect the heat of combustion per gram of candle
wax to be smaller than that of octane. The heat of combustion per mol of candle
wax, however, would be larger than that of octane.
41.
In general, the heat of combustion of oxygenated fuels is lower than the heat of
combustion of non-oxygenated fuels. The heat of combustion of MTBE is -3167
kJ/mol or -35.9 kJ/g. (Note H for the reaction is -6334 kJ, but this is for
combustion of 2 moles of MTBE, since in the balanced combustion reaction
MTBE has a coefficient of 2. Hence, we must divide by 2 to get the heat of
combustion per mole of MTBE.) Chemistry 08
53.
Spring 2010
n-octane and isooctane have the same heat of combustion because they have the
same number and type of bonds. The bonds are simply arranged differently in the
two molecules.