University:
Amherst College
Course:
CHEM 221 | Organic Chemistry I
Academic year:

2022
Views:

232

Pages:

3
Author:

tetangga0ml

— xt CUJL . 1 (a) For each compound below , how many separate signals would you expect to see in a ( room 13 temp) proton-decoupled C NMR spectrum, and how many in a * H NMR spectrum ? (In other * U many how words, f '* / / y of sets different H , ' > equivalent Cs and Hs are ~ 7 £> T O Write theypresent ?) \f \ xTT r *-~ * / O numbers in the spaces, / . y T' provided . ^ d ( >C / St* fZ t cr V v\ 4 £ 3 ( L £L a — 5“ ~c J M k ^ - 3 - l- /awod - j ^ / *» vs c^/ 3~ t* i -* - , 1 V tx ( M / Vv< 3 . 4 / -c- «-c ? 3>, ' - A * /1A>? - 5 sir 1(&> 1* OH f* ® s /ruc/t O& s» -e" // 7 I« 5 C ‘- '/ " ( K f> f « of M / 0 A -2. ^ V /JL 0,- yy X ( e - -7JM* , C W k -\ ^/ ^ Tv ^ ^Po ti JK V CKss. w v K, t v 1 l /. /0 0 Cl H C NMR signafs: pt * H NMR signals: Mcs ¥ ¥ v 1- CjJ S H 13 ' * ^— l° r / vc / ~L 4. A compound with the formula C 10 H10 displays IR stretches at about 3300 and 2150 cm- 1 . The compound's ' H NMR spectrum is shown. The number printed below the chemical shift scale are digital integrals (a ) Draw the structure , ( b) Draw a tree diagram to account for the splitting pattern of the 62%x V / > t < bd At Tr tx f T . I AT3 S ? tf I i I /( /V II I /> / II . 5 The ' id NMR spectrum of an ester with the formula C 12 H 14O3 is shown below (a) Draw the structure ( b ) Explain the dramatic downfield shift of the signal at 67.7. , , y: i v r ft / \ r / L \ \y( 4 O' ) 3 rc zrCM - ^ \ - ', O r 3 Jjl UUUUl r 7 r >: / :*M*t U 5 4 6 ( ppm ) 3 r> • 3 /tx_ cfrK r. ^ sAr^ ^ / cx>s d _ 4 e_ J ^ - - /rAjtAj o J f> T*. * ,T 1 oc 4 ~ Cv £? — c& — CH i \ fyed A-*- ycV\ < ^ * ^ £? ^ — Clf — Clj- - VA r ^A " r r^ cos _ lj> d /L*-S< - fcs dU*-/ fra^S < /, A, S d-c^ ^ i-C. MC7 <5/ ^ . "Z ~ ( s.'^ & ' ^ 5 cU* ' l /ZvQ /3 / VA' 6t ? ~ /y spiff? IVV 5* ^,- C dAcf -ed /e rS " c S> C7 ' ' ^ , ^ ov - fe £> ^UU5 w* * c^ rs ^^ ’ - e /i . ^ * fc. } IA ~, &* ed w 7 s^ ed -C + 0 - -tL 5? —. fc &Z^ [ W’ Cw'" 'N G C, oH /1-*. £ ^ ^ ~ Zv* d sh' c /ut ^ -e. + iA w £ < IA skedloJ - ot ^ - U*A e. ~~- Ar ' kvJ*^ •» j . HJ lncA~/ C4 S 7< ^ cJ rvv > — Li , • Cv ) ^ cv~<- i ) & * —do** /(^ |A«/X<_ GlYC**~yad / • f v c, ^ OIAJ |w 4i ^ li ^ « * /» /t-x • s. rx o <~‘!~' S'r $ £e* —^ < C .4 ; )riA (y J J/ / «7 */*» ^/,- —wOydc / r 75 <> «" ^ /^ <_ - ^ Lf V <- ~ ** © rev 4 / * e> •'0'’ ^d rs u bovdLd ' J’3\ V ° $t e.cJ~ 4 \ N h»sJ}? h( pjlui. J- /£ «A 5 1 * ( « «/« / 1 c& ArJLfr e ^ 0 * / ^ ^ ^ ^OA K i O c u ~<_ V / Z/' < — v \ o A ~ jhdldkr /A ;-v ic cJoo J- fUA~ ZJt \ ) jx: /7*5 ^ S do** cd c «i . ° Seeded r * * v< 5 A ,'Vc/, c <_ 7r // o - pcAS 7 ' ^ ^ .« - vcdLd ) J 5 f* / / . -^ - ^7 AA «// ^>^ CXi vAc x ) g JTX ^ \« \ x- A-*- ' c? lAO* 2Tw / \A UJ t 3 IASS 1 cy ^ \‘ fl^_ -txc . - ^ ^e7 Lc t*~- >V j c v l t

Chemistry 22 Homework Set 3 Solutions

Related Documents

Description

Related Documents

Free up your schedule!

Take 5 seconds to unlock