University:
California Institute of Technology
Course:
ACM 206 | Topics in Computational Mathematics
Academic year:

2020
Views:

395

Pages:

2
Author:

StellarSymphony

�в Name -------------- Factoring ах 2 + Ьх + с Wrong! 12х 2 - 2х-:- 4 = 12х 2 - 2х-4 = ( 12х +4 )(х- 1) - Q UIC • k (Зх-2)(4х+2) Rev1ew Use the FOIL method to test your answer and check that the middle term is correct. (12х + 4)(х - 1) (Зх- 2)(4х + 2) = 12х2 - 12х + 4х - 4 = 12х2 6х- Sx- 4 12х2 = 12х2 + = - - 8х- 4 2х- 4 Wrong! .... Right! Factor each expression. Use the code to answer this riddle: Wлatdid 1Ье distraught geometry teacher keep repeating wheJ) he found the empty parrof cage? 1. 2. r 4. 5. 6. 1. 8. 9. 10. J/x ) Jx -t 3 Sx -t у.?- �x+z) .::: 4-&--ZJ�-: ) 6х 2-7х-10 = ( -fS (_х-2-)( 9х 2+ 37х +4= '[ -+t) 2 7х + 5х-2 = [ -+ ) -:;.х. ф q)(+ l)l � Зх 2 - 8х - 3 = L3x-+ l_)L..X- з) +1..\\ 2х 2-Вх + 8 = �-1../х \)(1.x..-t \ 12х 2 + 8х + 1 = t>)( + 11. вх 2+11х-10= 12. 6х 2 + 1ох + 4 = 13. Зх 2+6х - 9 = 14. 2х 2+27х + s1 = с:с l2:x -1 cr.'::( _,, 3(.х-т cr --- -- -- -- -- --' 8 S 2 10 4 14 11 3 � G (2х - 1)(4х+ 1) о (6х+ S)(x-2) L (5х+9)(х+3) L (3х + 4)(х + 2) v (2х-4)(х-2) v (6х + 1)(2х+ 1) N (J__-+ .) (i<_-) (9х+1)(х+4) (7х - 2)(х+ 1) (8х-5)(х +2) о (2х + 9)(х + 9) Р (Зх + 1)(х - 3) о Р (2х+2)(Зх+2) (Зх - З)(х+ 3) ------13 7 З 9 - (2х-2)(2х-4) о i-x-:S"'j.y....-t2..,,) 3(_:х?-+ 'lx-3) � ,\ G N z&- -2.X,)<--"ZJ 2-(]л/-+бх-tz-) = z{__3x. + � 11� Нх 2 - 2х - 1 = L + 1 'j_2;< - 1 ) Зх 2+ 10х +8 = (_;ь� --+ч)(х + 2 Sx 2+ 24х +27 = ( 4х 2 - 12х +8 = -- //, '1' 1 12 6 iB Name -------------- Factoring х 2 + Wrong! Ьх + с х 2 - 5х-24 = (х-8)(х + 3) Right! Quick Review ------------------------ When the last term is positive, the signs in both factors will match the middle term of the trinomial. When the last term is negative, the factors will have opposite signs. Factor each expression. Use the code to answer this riddle: What did the algebra book say to the Ьiology book? 1. 2� ..Д з. 4. (x-3)(x_-2-,J х 2 - 5х+ 6= l"'- +&;Х -t-=t) х -11х+30 = D<..-'5XX- Le) х 2+ 10х+2 1 = 0(-+�)(Х. -t -=;) х + 14х+ 45 = (х т ) L-к + 9 s) х 2+ 1Зх+ 42 = 2 х 2-12х+32= 7. х 2 - 11х+ 18 = s. х +8х-48= 9. х 2 - 8х-33= 10. х 2+ 11х+ 10 = 11. х 2 - х-56= 12. 1з. 14. 15. х 2+2х-15 = + \2..-"')lx Lx -\ 2 11 +Б) (?(+�) (х-7 ---6 -+') З (х-2)(х-3) G (х + 6)(х + Р-.... (х-4)(х-8J 10 1 2 (х+ 7)(х+3) м (х+ 12)(х-4) о (х-З)(х + 5) 9) &-+ <е) х 2-3х-40= {:х-3)6. 12 Е L )(х--+ � ') Cx-t 10)(: -t t� iY� 4 +) х + 15х+ 54= ()( + ___ 11 Сх -4 LX -�) 6<.➔ 5)&-з) 2 (х+ 9)(х + 5) (х + 3)(х-11) 6<- х +2х-63 = в Lx-L\)Lx.-ъ) ("'- 2 (х-5)(х-6) н 2 6. д 12 15 Р (х-2)(х-9) R (х-8)(х + 5) s (х+ 9)(х � 6) т (х+ 9)(х-7) V (х + 1 О)(х+ 1) w (х + 7)(х-8) ------7 14 12 5 4 1 8