Answers - Arbitrage-Free Valuation Framework

Question #1 of 30 Question ID: 1473453 For a 3-year, semiannual coupon payment bond, the number of interest rate paths that would be generated using the pathwise valuation is closest to: A) 64 B) 4 C) 32 Explanation For a 3-year, semiannual coupon bond, there will be six nodal periods resulting in 2(6-1) = 32 paths. (Module 26.2, LOS 26.g) Question #2 of 30 Question ID: 1473440 Which of the following choices is least-likely a property of a binomial interest rate tree? A) Higher volatility at higher rates. B) Mean reversion of interest rates. C) Non-negative interest rates. Explanation A binomial interest rate tree has two desirable properties: non-negative interest rates and higher volatility at higher rates. Binomial trees do not force mean reversion of rates. (Module 26.1, LOS 26.c) Question #3 of 30 Question ID: 1473459 A binomial model or any other model that uses the backward induction method cannot be used to value a mortgage-backed security (MBS) because: A) B) the cash flows for the MBS are dependent upon the path that interest rates follow. the cash flows for an MBS only depend on the current rate, not the path that rates have followed. C) the prepayments occur linearly over the life of an interest rate trend (either up or down). Explanation A binomial model or any other model that uses the backward induction method cannot be used to value an MBS because the cash flows for the MBS are dependent upon the path that interest rates have followed. (Module 26.2, LOS 26.h) Question #4 of 30 Question ID: 1473438 Tim Brospack is generating a binomial interest rate tree assuming a volatility of 15%. Current 1-year spot rate is 5%. The 1-year forward rate in the second year is either a low estimate of 5.250% or a high estimate of 7.087%. The middle 1-year forward rate in year three is estimated at 6.25%. The upper node 1-year forward rate in year three is closest to: A) 8.437% B) 7.747% C) 6.445% Explanation Upper node interest rate = 6.25 × e2×0.15 = 8.437% (Module 26.1, LOS 26.c) Question #5 of 30 Question ID: 1473441 Which of the following choices is least-likely a property of a binomial interest rate tree? A) Higher volatility at higher rates. B) Non-negative interest rates. C) Adjacent forward rates in a nodal period are one standard deviation apart. Explanation A binomial interest rate tree has two desirable properties: non-negative interest rates and higher volatility at higher rates. Additionally, adjacent forward rates in a nodal period are two standard deviations apart. (Module 26.1, LOS 26.c) Question #6 of 30 Question ID: 1473456 A 3-year, 3% annual pay, $100 par bond is valued using pathwise valuation. The interest rate paths are provided below: Path Year 1 Year 2 Year 3 1 2% 2.8050% 4.0787% 2 2% 2.8050% 3.0216% 3 2% 2.0780% 3.0216% 4 2% 2.0780% 2.2384% The value of the bond in path 2 is closest to: A) $100.88 B) $102.72 C) $101.15 Explanation Path 2 value = 3.0 (1.02) 3.0 + (1.02)(1.02805) 103.0 + (1.02)(1.02805)(1.030216) = 101.15 (Module 26.2, LOS 26.g) Question #7 of 30 Question ID: 1473464 Jill Sebelius, editor-in-chief of a monthly interest-rate newsletter uses the following model to forecast short-term interest rates: dr = a(b − r) dt + σ√rdz For the current newsletter, Sebelius has issued the following expectations: a=0.40, b = 3%, r = 2%. According to the model used by Sebelius, volatility in the short-term in interest rate is most likely: A) positively related to the current level of the short-term interest rate. B) independent of the current level of the short-term interest rate. C) negatively related to the current level of the short-term interest rate. Explanation Under the Cox-Ingersoll-Ross model, the random or stochastic component incorporates the square root of current level of interest rate. Hence the higher the current level of interest rates, the higher the volatility of interest rates. (Module 26.3, LOS 26.i) Question #8 of 30 Question ID: 1473461 Currently the term structure of interest rate is downward sloping. Which of the following models most accurately describe the current term structure? A) Cox-Ingersoll-Ross model. B) Ho-Lee model. C) Vasicek model. Explanation Ho-Lee model is an arbitrage-free term structure that is calibrated to the current actual term structure (regardless of whether it is upward or downward sloping). Vasicek and CoxIngersoll-Ross model are examples of equilibrium term structure models and may generate term structures inconsistent with current market observations. (Module 26.3, LOS 26.i) Question #9 of 30 Question ID: 1473449 Sam Roit, CFA, has collected the following information on the par rate curve, spot rates, and forward rates to generate a binomial interest rate tree consistent with this data. Maturity Par Rate Spot Rate 1 5% 5.000% 2 6% 6.030% 3 7% 7.097% The binomial tree generated is shown below (one year forward rates) assuming a volatility level of 10%: 0 1 5% 2 7.7099% C A 9.2625% B Riot also generated another tree using the same spot rates but this time assuming a volatility level of 20% as shown below: 0 1 5% 2 8.9480% 13.8180% 5.9980% 9.2625% 6.2088% The one-year forward rate represented by 'A' is closest to: A) 5.4223% B) 6.3123% C) 6.7732% Explanation Value represented by 'A' = 7.7099 / e2x0.10 = 6.3123% (Module 26.2, LOS 26.d) Question #10 of 30 Question ID: 1473462 Jill Sebelius, editor-in-chief of a monthly interest-rate newsletter uses the following model to forecast short-term interest rates: dr = a(b − r) dt + σ√rdz For the current newsletter, Sebelius has issued the following expectations: a=0.40, b = 3%, r = 2%. Based on Sebelius's estimates, over a sufficiently long period of time, the expected value of the short-term interest rate is closest to: A) 2.4% B) 3% C) 2% Explanation The long-term expected value of short-term rates is the mean reverting level (b) estimated by Sebelius to be 3%. (Module 26.3, LOS 26.i) Question #11 of 30 Question ID: 1473455 A 3-year, 3% annual pay, $100 par bond is valued using pathwise valuation. The interest rate paths are provided below: Path Year 1 Year 2 Year 3 1 2% 2.8050% 4.0787% 2 2% 2.8050% 3.0216% 3 2% 2.0780% 3.0216% 4 2% 2.0780% 2.2384% The value of the bond in path 4 is closest to: A) $100.02 B) $102.58 C) $101.88 Explanation Path 4 value = 3.0 3.0 + (1.02) 103.0 + (1.02)(1.02078) (Module 26.2, LOS 26.g) = 102.58 (1.02)(1.02078)(1.022384) Question #12 of 30 Question ID: 1473435 The process of stripping is most likely to be used to earn arbitrage profits in a situation where: A) a portfolio of treasury strips is trading for a lower price than an intact treasury bond. B) Security valuations are not consistent with the value additivity principle. C) one treasury bond trades at a lower price than another treasury bond with identical characteristics. Explanation If the principle of value additivity holds, it will not be possible to earn arbitrage profits through stripping (or reconstitution). If a portfolio of strips is trading for less than the price of an intact bond, one can purchase the strips, combine them ("reconstitution"), and sell them as a bond. Similarly, if the bond is worth less than its component parts, one could purchase the bond, break it into a portfolio of strips ("stripping"), and sell those components. When one security trades at a lower price than another security with identical characteristics, this is known as dominance, and the arbitrage required to earn a profit involves going long the underpriced security and short the overpriced security. (Module 26.1, LOS 26.a) Question #13 of 30 Question ID: 1473439 Tim Brospack is generating a binomial interest rate tree assuming a volatility of 15%. Current 1-year spot rate is 5%. The 1-year forward rate in the second year is either a low estimate of 5.250% or a high estimate of 7.087%.The middle 1-year forward rate in year three is estimated at 6.25%. The lower node 1-year forward rate in year three is closest to: A) 6.747% B) 5.342% C) 4.63% Explanation Lower node interest rate = 6.25 / e2×0.15 = 4.63% (Module 26.1, LOS 26.c) Question #14 of 30 Question ID: 1473451 Sam Roit, CFA, has collected the following information on the par rate curve, spot rates, and forward rates to generate a binomial interest rate tree consistent with this data. Maturity Par Rate Spot Rate 1 5% 5.000% 2 6% 6.030% 3 7% 7.097% The binomial tree generated is shown below (one year forward rates) assuming a volatility level of 10%: 0 1 5% 2 7.7099% C A 9.2625% B Roit also generated another tree using the same spot rates but this time assuming a volatility level of 20% as shown below: 0 1 5% 2 8.9480% 13.8180% 5.9980% 9.2625% 6.2088% Is the binomial tree using the 20% volatility assumption calibrated properly? A) The tree is not calibrated properly because it is not consistent with market prices. B) The tree is calibrated properly. C) The tree is not calibrated properly because adjacent nodes are not appropriate standard deviations apart. Explanation The tree is not calibrated properly – it does not value 3-year 7% bond at par (i.e., the market price): V2,UU = 107 (1.13818) = $94.01 V2,UL = 107 (1.092625) = $97.93 V2,LL = 107 1.062088 = $100.74 V1,U = 94.01 +97.93 1 1.08948 × [ 2 + 7] = $94.51 V1,L = 97.93 + 100.74 1 1.05998 × [ 2 + 7] = $100.31 V0 = 94.51 + 100.32 1 1.05 × [ 2 + 7] = $99.44 The adjacent nodes in the binomial tree for any nodal period are all two standard deviations apart. (Module 26.2, LOS 26.d) Question #15 of 30 Question ID: 1473450 Sam Roit, CFA, has collected the following information on the par rate curve, spot rates, and forward rates to generate a binomial interest rate tree consistent with this data. Maturity Par Rate Spot Rate 1 5% 5.000% 2 6% 6.030% 3 7% 7.097% The binomial tree generated is shown below (one year forward rates) assuming a volatility level of 10%: 0 1 5% 2 7.7099% C A 9.2625% B Roit also generated another tree using the same spot rates but this time assuming a volatility level of 20% as shown below: 0 1 5% 2 8.9480% 13.8180% 5.9980% 9.2625% 6.2088% The one-year forward rate represented by 'B' is closest to: A) 7.5835% B) 7.4223% C) 8.7732% Explanation Value represented by 'B' = 9.2625 / e2x0.10 = 7.5835% (Module 26.2, LOS 26.d) Question #16 of 30 Question ID: 1473457 A 3-year, 3% annual pay, $100 par bond is valued using pathwise valuation. The interest rate paths are provided below: Path Year 1 Year 2 Year 3 1 2% 2.8050% 4.0787% 2 2% 2.8050% 3.0216% 3 2% 2.0780% 3.0216% 4 2% 2.0780% 2.2384% The value of the bond in path 1 is closest to: A) $98.77 B) $101.88 C) $100.18 Explanation Path 1 value = 3.0 (1.02) 3.0 + (1.02)(1.02805) 103.0 + (1.02)(1.02805)(1.040787) = 100.18 (Module 26.2, LOS 26.g) Question #17 of 30 Question ID: 1473463 Jill Sebelius, editor-in-chief of a monthly interest-rate newsletter uses the following model to forecast short-term interest rates: dr = a(b − r) dt + σ√rdz For the current newsletter, Sebelius has issued the following expectations: a=0.40, b = 3%, r = 2%. Sebelius's model is most accurately described as the: A) Cox-Ingersoll-Ross model. B) Ho-Lee model. C) Vasicek model. Explanation The model given is an example of the Cox-Ingersoll-Ross model which differs from the Vasicek model by including the square root of current level of short-term interest rates in the stochastic part of the equation. (Module 26.3, LOS 26.i) Question #18 of 30 Question ID: 1473448 Sam Roit, CFA, has collected the following information on the par rate curve, spot rates, and forward rates to generate a binomial interest rate tree consistent with this data. Maturity Par Rate Spot Rate 1 5% 5.000% 2 6% 6.030% 3 7% 7.097% The binomial tree generated is shown below (one year forward rates) assuming a volatility level of 10%: 0 1 5% 2 7.7099% C A 9.2625% B Riot also generated another tree using the same spot rates but this time assuming a volatility level of 20% as shown below: 0 1 5% 2 8.9480% 13.8180% 5.9980% 9.2625% 6.2088% The one-year forward rate represented by 'C' is closest to: A) 8.7732% B) 7.4223% C) 11.3132% Explanation Value represented by 'C' = 9.2625 x e2x0.10 = 11.3132% (Module 26.2, LOS 26.d) Question #19 of 30 Question ID: 1473436 The government bond spot rate curve is given below: Maturity (years) Spot rate 0.5 1.25% 1.0 1.30% 1.5 1.80% 2.0 2.00% 2.5 2.20% 3.0 2.25% 3.5 2.28% 4.0 2.30% Compute the issue price of a 3-year, 3% semiannual coupon government bond with a par value of $100. A) $102.20 B) $104.09 C) $102.15 Explanation Value = 1.50 [1+ 0.0125 2 1.50 1 ] 1.50 + [1+ 0.013 2 2 ] 1.50 + [1+ 0.018 2 3 ] 1.50 + [1+ 0.02 2 4 ] [1+ 0.022 2 = $102.20 (Module 26.1, LOS 26.b) Question #20 of 30 Question ID: 1473437 Government par curve is provided below: Maturity (years) Par rate 1 5.0% 2 6.0% 3 6.5% 4 7.0% The value of a 4-year, 5% annual pay, $100 par government bond is closest to: 101.50 + 5 ] + [1+ 0.0225 2 6 ] A) $98.49 B) $101.12 C) $93.15 Explanation Answer: First we compute the spot rates: S1: (given) = 5% S2: 100 = 6.0 106.0 + (1.05) (1+S2 ) → S2 = 6.03% 2 S3: 100 = 6.5 6.5 (1.05) + (1.0603) 106.5 + 2 (1+S3 ) → S3 = 6.56% 3 S4: 100 = 7.0 7.0 + (1.05) (1.0603) 7.0 + 2 (1.0656) 107.0 + 3 (1+S4 ) → S4 = 7.10% 4 Then we use the spot rates to value the 4-year, 5% annual pay bond: Value = 5.0 (1.05) 5.0 1 + (1.0603) 5.0 2 + (1.0656) 105.0 3 + (1.071) 4 = 93.15 (Module 26.1, LOS 26.b) Question #21 of 30 Question ID: 1473460 Relative to the binomial model, Monte Carlo method is most likely: A) less flexible in forcing interest rates to mean revert. B) more flexible as it does not need a volatility estimate. C) more suitable when valuing securities whose cash flows are interest rate path dependent. Explanation Monte Carlo method does not require that cash flows of a security be path independent and hence is suitable alternative to the binomial model to value securities such as mortgage backed securities whose cash flows are path dependent. The model generating interest rates paths in a Monte Carlo simulation is based on an assumed level of volatility (i.e., model needs a volatility input). The model generating interest rates in a Monte Carlo simulation can incorporate bounds for interest rates to force mean reversion of rates. Such bounded optimization is not possible in a binomial model. (Module 26.2, LOS 26.h) Question #22 of 30 Question ID: 1473444 Which of the following is a correct statement concerning the backward induction technique used within the binomial interest rate tree framework? From the maturity date of a bond: A) the corresponding interest rates and interest rate probabilities are used to discount the value of the bond. B) a deterministic interest rate path is used to discount the value of the bond. C) the corresponding interest rates are weighted by the bond's duration to discount the value of the bond. Explanation For a bond that has N compounding periods, the current value of the bond is determined by computing the bond's possible values at period N and working "backwards" to the present. The value at any given node is the probability-weighted average of the discounted values of the next period's nodal values. (Module 26.1, LOS 26.e) Question #23 of 30 Question ID: 1473445 A bond with a 10% annual coupon will mature in two years at par value. The current oneyear spot rate is 8.5%. For the second year, the yield volatility model forecasts that the oneyear rate will be either 8% or 9%. Using a binomial interest rate tree, what is the current price? A) 103.572. B) 102.659. C) 101.837. Explanation The tree will have three nodal periods: 0, 1, and 2. The goal is to find the value at node 0. We know the value in nodal period 2: V2=100. In nodal period 1, there will be two possible prices: V1,U=[(100+10)/1.09+(100+10)/1.09]/2= 100.917 V1,L=[(100+10)/1.08+(100+10)/1.08]/2= 101.852 Thus V0=[(100.917+10)/1.085+(101.852+10)/1.085]/2= 102.659 (Module 26.1, LOS 26.e) Question #24 of 30 Question ID: 1473458 Increasing the number of paths generated in a Monte Carlo simulation is most likely to increase the: A) fundamental accuracy of the estimated value. B) statistical accuracy of the estimated value. C) utility of the model. Explanation Increasing the number of paths would increase the statistical accuracy of the estimate but does nothing for the fundamental accuracy of the estimated value which depends on the quality of model inputs. Model utility depends on valuation accuracy of the model and hence would not increase as we increase the number of paths. (Module 26.2, LOS 26.h) Question #25 of 30 Question ID: 1473442 Why is the backward induction methodology used to value a bond rather than a forward induction scheme? A) The convexity of a bond changes over time. B) Future interest rate changes are difficult to forecast. C) The price of the bond is known at maturity. Explanation The objective is to value a bond's current price while the bond price at maturity is known. Therefore, price at maturity is used as a starting point, and we work backward to the current value. (Module 26.1, LOS 26.e) Question #26 of 30 Question ID: 1473443 With respect to interest rate models, backward induction refers to determining: A) one portion of the yield curve from another portion. B) the current value of a bond based on possible final values of the bond. C) convexity from duration. Explanation Backward induction refers to the process of valuing a bond using a binomial interest rate tree. For a bond that has N compounding periods, the current value of the bond is determined by computing the bond's possible values at period N and working "backwards." (Module 26.1, LOS 26.e) Question #27 of 30 Question ID: 1473446 Using the following interest rate tree of semiannual interest rates what is the value of an option free bond that has one year remaining to maturity and has 5% coupon rate with semi-annual coupon payments. Today 6 Months 7.30% 6.20% 5.90% A) 98.98. B) 98.67. C) 97.53. Explanation The option-free bond price tree is as follows: 100.00 A → 98.89 98.67 100.00 99.56 100.00 As an example, the price at node A is obtained as follows: PriceA = (prob × (Pup + (coupon / 2)) + prob × (Pdown + (coupon / 2)) / (1 + (rate / 2)) = (0.5 × (100 + 2.5) + 0.5 × (100 + 2.5) / (1 + (0.0730 / 2)) = 98.89. The bond values at the other nodes are obtained in the same way. The calculation for node 0 or time 0 is 0.5[(98.89 + 2.5) / (1+ 0.062 / 2) + (99.56 + 2.5) / (1 + 0.062 / 2)] = 0.5(98.3414 + 98.9913) = 98.6663 (Module 26.1, LOS 26.e) Question #28 of 30 Question ID: 1473454 A 3-year, 3% annual pay, $100 par bond is valued using pathwise valuation. The interest rate paths are provided below: Path Year 1 Year 2 Year 3 1 2% 2.8050% 4.0787% 2 2% 2.8050% 3.0216% 3 2% 2.0780% 3.0216% 4 2% 2.0780% 2.2384% The value of the bond in path 3 is closest to: A) $99.88 B) $100.02 C) $101.85 Explanation Answer: Path 3 value = 3.0 3.0 + (1.02) 103.0 + (1.02)(1.02078) = 101.85 (1.02)(1.02078)(1.030216) (Module 26.2, LOS 26.g) Question #29 of 30 Question ID: 1473447 Using the following interest rate tree of semiannual interest rates what is the value of an option free semiannual bond that has one year remaining to maturity and has a 6% coupon rate? 6.53% 6.30% 5.67% A) 97.53. B) 99.81. C) 98.52. Explanation The option-free bond price tree is as follows: 100.00 A ==> 99.74 99.81 100.00 100.16 100.00 As an example, the price at node A is obtained as follows: PriceA = (prob × (Pup + coupon/2) + prob × (Pdown + coupon/2))/(1 + rate/2) = (0.5 × (100 + 3) + 0.5 × (100 + 3))/(1 + 0.0653/2) = 99.74. The bond values at the other nodes are obtained in the same way. The calculation for node 0 or time 0 is 0.5[(99.74 + 3)/(1+ 0.063/2) + (100.16 + 3)/(1 + 0.063/2)] = 99.81 (Module 26.1, LOS 26.e) Question #30 of 30 Question ID: 1473452 Suppose that we calculate the value of an option-free, fixed-rate coupon bond, discounting the cash flows using two methods: I. the zero-coupon yield curve. II. an arbitrage-free binomial lattice. Compared to the first methodology, the second method is expected to produce: A) a lower value if the bond carries a coupon higher than the corresponding benchmark bond. B) the same value. C) a higher value in the presence of volatility. Explanation Because these two valuation methods are arbitrage-free, the two values obtained must be the same. An option-free bond that is valued by discounting by the spot rates should have the same value as if the binomial interest rate tree was used. (Module 26.2, LOS 26.f)