University:
Campbell University
Course:
CHEM 111 | General Chemistry I
Academic year:

2019
Views:

293

Pages:

2
Author:

Accouppayonna660

**Mole Calculations Continued** **Name:** **6. Calculate the number of moles contained in the following.** a) 10.6 L of SO2(g) at STP 10.6 L SO2 * (1 mol SO2 / 22.4 L SO2) = 0.473 mol SO2 b) 7.50 x 10^21 molecules of HNO3 7.50 x 10^21 molecules HNO3 * (1 mol HNO3 / 6.022 x 10^23 molecules HNO3) = 0.0125 mol HNO3 c) 425 mg of Ca(OH)2 425 mg Ca(OH)2 * (1 g / 1000 mg) * (1 mol Ca(OH)2 / 74.1 g Ca(OH)2) = 0.00574 mol Ca(OH)2 d) 4.25 x 10^12 molecules of Fe2O3 4.25 x 10^12 molecules Fe2O3 * (1 mol Fe2O3 / 6.022 x 10^23 molecules Fe2O3) = 7.06 x 10^-12 mol Fe2O3 e) 0.950 kg of NaOH 950 g NaOH * (1 mol NaOH / 40.0 g NaOH) = 23.8 mol NaOH f) 25.0 mL of N2(g) at STP 0.0250 L N2 * (1 mol N2 / 22.4 L N2) = 0.00112 mol N2 g) 5.50 x 10^25 molecules of CCl4 5.50 x 10^25 molecules CCl4 * (1 mol CCl4 / 6.022 x 10^23 molecules CCl4) = 91.3 mol CCl4 h) 0.120 L of NO2(g) at STP 0.120 L NO2 * (1 mol NO2 / 22.4 L NO2) = 0.00536 mol NO2 **7. Calculate the volume of the following gases at STP.** a) 0.235 mol of B2H6 0.235 mol B2H6 * (22.4 L B2H6 / 1 mol B2H6) = 5.26 L B2H6 b) 9.36 mol of SiH4(g) 9.36 mol SiH4 * (22.4 L SiH4 / 1 mol SiH4) = 210 L SiH4 c) 2.5 x 10^3 mol of C2H6(g) 2.5 x 10^3 mol C2H6 * (22.4 L C2H6 / 1 mol C2H6) = 56000 L C2H6 **8. Calculate the mass of each of the following.** a) 0.125 mol of CO2(g) at STP 0.125 mol CO2 * (44.01 g CO2 / 1 mol CO2) = 5.50 g CO2 b) 5.48 mol of FeCl3(s) 5.48 mol FeCl3 * (162.2 g FeCl3 / 1 mol FeCl3) = 889 g FeCl3 c) 6.54 x 10^-4 mol of HCN(g) at STP 6.54 x 10^-4 mol HCN * (27.01 g HCN / 1 mol HCN) = 0.0177 g HCN d) 15.4 mol of Ni(OH)2(s) 15.4 mol Ni(OH)2 * (92.71 g Ni(OH)2 / 1 mol Ni(OH)2) = 1430 g Ni(OH)2