University:
Campbell University
Course:
CHEM 111 | General Chemistry I
Academic year:

2021
Views:

380

Pages:

3
Author:

Chanel Morton

PlrroiOS ' in J ' tcafit e - f> 0 Name POLARITY OF MOLECULES . 470 F H 4> Determine whether the following molecules are polar or nonpolar . N2 1 - * ,o N N 1* 0 . 7 .^ COz Polar 3 - 2 Z1 .' Polar . O = C - O .r T 3, Z77 HF l\)on p oioT ' 2 H20 . > * 2.1 l CH3OH a - \l it - t - « 7r Po lor . . 2. S 9 H2S “ S*‘ ?, 2.5T 3 . 8 - 2 1 2 vl Polar A/ tfh y d a s . 4 NH3 Z,< — ti Z, 3, 0 N H . Z ' K 'T t 10. I2 . CH4 A/ o , 4' ^ —^ft2 ‘ £ - 2.. C . i r 2 C i PO (JM~ 5 * n. 2.1 H CHCI3 - 3,04 H . /6( ' r < 1 SOs . 3r * • * lf ) 5,0 C) po lar 12. 02 ?,r o -o ' po \asf Chemistfy IF8766 Z if J ’O /V o /t po \ *e r . > ]ar I z » 6 £» N on ©Instructional Fair, Inc. KEY Polarity Name 1.) Which of the following molecules will be polar and which will be nonpolar? s sJ. \ B Cl Cl / H \ c / H O 9-) \ — C— C — H H y 0 c= o H Mg H o H H H f .) H H H — C — Cl Cl Cl y d.) H oA Cl b.) S / O O H H 2.) Examine the following melting temperatures. All the molecules are not polar. NH3 = -78°C PH3 = -133°C ASH3 = -116°C a.) Why do the melting temperatures of SbH3 AsH3 and PH3 steadily ( Answer SbH3 = -88°C decrease? - Sb, As and P in this order have decreasing electron numbers. The more electrons you have the greater your London forces are (temporary dipole). The greater your London forces are the higher your melting point is. b.) Why does the melting temperature of NH3 suddenly increase going from PH3 up to NH3? Answer - NH3 has a nitrogen bonded to hydrogen. This means there is hydrogen bonding occurring along with the London forces, whereas PH3 only has London forces, which leads to a big jump up in the melting temperature. 3.) Which of the following substances would you expect to involve hydrogen bonds between like molecules? a.) CH4 c.) b.) HCI d.) H2S Hz0 y CH3-NH2 y CH3-CH2-OH f .) CH3 -SH y HF 1 KEY 4.) Suggest a reason why liquid propane has a very low viscosity, whereas liquid glycerine has a very high Propane = CH3-CH2-CH3 viscosity. glycerine = CHz CH — CHz y OH OH OH Answer - Propane ' s viscosity is much lower because there are less forces and they are weaker than the forces in glycerine. The glycerine has both hydrogen and London forces while propane is just weak London forces. High forces lead to high viscosity. 5.) Classify each of the following with respect to the most important type(s) of bonding or forces(s) existing between the particles. a.) 2 molecules of O2 in O2 (s) London Forces b.) 2 atoms of Xe in Xe (s) London Forces c.) An atom of C and an atom of Cl in CCU Covalent Bond d.) 2 molecules of CH3F in CH3F (I) Hydrogen bonding e.) F and Cs in CsF (s) Ionic bond f.) atoms of He and Kr London Forces 6.) Which should melt at a higher temperature and why? a.) He or Xe Answer - Xe larger London forces b.) HBr and Kr Answer - HBr has dipole-dipole c.) CH3-CH3 or HO-CH2-CH2-OH Answer - HO-CH2-CH2-OH has hydrogen bonding d.) F2 or Br 2 Answer - Brz larger London forces . ... "Ohhhhhhh Look al that Schuster * „ Dags are so cute when they tiy to amprahnnd quantum mechanics " . 2

Molecular Polarity Worksheet Answer Key

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