University:
College
Course:
College Chemistry
Academic year:

2022
Views:

466

Pages:

2
Author:

5CelestialChronicle

Equation Stoichiometry Chemistry 110 1] Given the equation: 2C8H18 + 25 O2 ----> 16CO2 + 18H2O a. How many moles of oxygen gas are required to make 8.33 moles of carbon dioxide? 25mol O2 8.33 moles CO2 X 16mol CO = 13.0 moles O2 2 Answer ___________________ b. How many moles of C8H18 must be used to produce 1.99 grams of water 1.99 mg H2O X 1mol H2O 2mol C8H18 X 18mol H O = 1.23 x 10-2 mol C8H18 18.0g 2 Answer ___________________ c. If the reaction produces 5.3 mg of carbon dioxide how many grams of water are produced? 1mol CO2 18mol H2O 18.0g H2O 10-3g 5.3mg CO2 X 1mg X 44.0g CO X 16mol CO X 1mol H O = 2 2 2 2.4 x 10-3 g H2O Answer ___________________ 24 d. How many grams of oxygen are needed to react with 7.22 x 10 molecules of C8H18? 7.22 x 1024molec. C8H18 X 1mol C8H18 6.02x1023molec 25mol O2 X 2mol C H 8 18 32.0g O2 X 1mol O = 2 4.80 x 103g O2 Answer ___________________ 2] How many grams of aluminum oxide are formed when 25.0 grams of Aluminum are reacted with oxygen gas? a. Write the balanced equation 4 Al + 3 O2 ---> 2 Al2O3 b. Calculate the number of grams of aluminum oxide produced 1mol Al2O3 102.0g Al2O3 1mol Al 25.0g Al X 27.0g Al X 2mol Al X 1mol Al O = 47.2g Al2O3 2 3 Answer ___________________ 3] A sample of TiCl4 is reacted with Titanium metal to produce Titanium (III) chloride a. Write the balanced equation 3 TiCl4 + Ti ---> 4 TiCl3 b. How many kg of Titanium (III) chloride was produced from 52 kg of Titanium (IV) chloride? 1mol TiCl4 154.4g TiCl3 10-3Kg 4mol TiCl3 103g 52 Kg TiCl4 X 1Kg X 189.9g TiCl X .3mol TiCl X 1mol TiCl X 1g = 4 4 3 56.4 Kg TiCl3 Answer ___________________ 4] Given the equation: Al4C3 + 12 H2O ---> 4Al(OH)3 + 3 CH4 a. How many grams of water are needed to react with 100.0 moles of Al4C3? 12mol H2O 18.01g H2O 100.0mol Al4C3 X 1mol Al C X 1mol H O = 2.160 x 104g H2O 4 3 2 Answer ___________________ b. How many moles of Al4C3 were reacted when 3.55 x 10 35 formulas units of aluminum hydroxide were produced? 3.55 x 1035 formula units Al(OH)3 X 1mol Al(OH)3 6.02 x 1023 form. units 1mol Al4C3 X 4mol Al(OH) 3 = 1.47 x 1011mol Al(OH)3 Answer ___________________ c. How many grams of aluminum hydroxide were produced when 673 mg of CH4 were formed.? 1mol CH4 4mol Al(OH)3 78.0g Al(OH)3 10-3g X 1mol Al(OH) = 673 mg CH4 X 1mg X 16.0g CH X 3mol CH 3 4 4 4.37g Al(OH)3 Answer ___________________ 5] Given the reaction: 4 C + Na2CO3 + N2 ---> 2 NaCN + 3 CO 181 grams of sodium carbonate were added to an excess of carbon and nitrogen. After the reaction finished, 35 g of of unreacted sodium carbonate remained. a. How many moles of carbon monoxide were produced? 181g total Na2CO3 - 35g unreacted Na2CO3 = 146 g Na2CO3 reacted 1mol Na2CO3 3mol CO 146g Na2CO3 X 106.0g Na CO X 1mol Na CO = 4.13 mol CO 2 3 2 3 Answer ___________________ b. How many grams of nitrogen gas reacted with the sodium carbonate? 146g Na2CO3 X 1mol Na2CO3 1mol N2 28.0g N2 X 1mol Na CO X 1mol N = 38.6 g N2 106.0g 2 3 2 Answer ___________________