University:
Felician University
Course:
MATH-231 | Geometry I
Academic year:

2022
Views:

117

Pages:

4
Author:

Clint W.

Solve each proportion. 1) 3/5 = x/25 x = 15 2) 2/m = 5 2m = 10 m = 5 State if the triangles in each pair are similar. Remember a) AA/SAS/SSS, b) prove it, and c) write similarity statement. 3) No, not enough info 4) Yes By SAS △GOF ~ △SOR Find the missing length. The triangles in each pair are similar. 5) x = 117 6) x = 14 Find the missing length indicated. Leave your answer in simplest radical form. 7) x = 5√11 8) x = 30 Find the missing length indicated. (Hint: use the Side-Splitter theorem.) 9) 12x = 320 - 20x 32x = 320 x = 10 10) 6x = 30 x = 5 Find the distance between each pair of points. 11) (3, 2), (8, -4) d = √[(3-8)² + (2-(-4))²] = √((-5)² + (6)²) = √(25 + 36) = √61 12) (0, 4), (1, 2) d = √[(0-1)² + (4-2)²] = √((-1)² + (2)²) = √(1 + 4) = √5 Find the slope between the points. 13) (4, 1), (3, 3) m = (1-3)/(4-3) m = -2/1 = -2 14) (0, -18), (15, 9) m = (-18-9)/(0-15) = -27/-15 = 9/5 Find the midpoint of the line segment with the given endpoints. 15) (7, 1), (-2, -3) MP = ((7-2)/2, (1-3)/2) = (5/2, -1) 16) (-1, -5), (3, 3) MP = ((-1+3)/2, (-5+3)/2) = (1, -1) Find the other endpoint of the line segment with the given endpoint and midpoint. 17) Endpoint: (5, 4), midpoint: (-10, -7) (x+5)/2 = -10 x+5 = -20 x = -25 (y+4)/2 = -7 y+4 = -14 y = -18 Solve for x. 18) x+120 = 110 x = -10 19) 6x+8 = 8x-6 14 = 2x x = 7