the bisection method is a Root finding method that applies to any continuous for which one knows two
values with opposite signs. The method consists of repeatedly bisecting the interval defined by these values
and then selecting the subinterval in which the function changes sign, and therefore must contain a root. It is
a very simple and robust method, but it is also relatively slow. Because of this, it is often used to obtain a
rough approximation to a solution which is then used as a starting point for more rapidly converging
methods. The method is also called the interval halving method f(x)
3
First, two numbers a and b have to be found such that
above function, a=1
and b=2 satisfy this criterion, as
f(a)= 13 − 1 − 2 = −2 ;
f(a)
and
f(b)
have opposite signs. For the
f(b)= 23 − 2 − 2 = 4
Lets C1= (1+2)/2 = 1.5
f(c1)= 1.5 3 − 1.5 − 2 = −0.125
Since f(c1 ) is positive, replace a=1.5 to ensure that for the next Iteration f(a) and f(b) have opposite signs Iteration
an
bn
cn
f(cn)
1
1
2
1.5
−0.125
2
1.5
2
1.75
1.6093750
3
1.5
1.75
1.625
0.6660156
4
1.5
1.625
1.5625
0.2521973
5
1.5
1.5625
1.5312500
0.0591125
6
1.5
1.5312500
1.5156250
−0.0340538
7
1.5156250
1.5312500
1.5234375
0.0122504
8
1.5156250
1.5234375
1.5195313
−0.0109712
9
1.5195313
1.5234375
1.5214844
0.0006222
10
1.5195313
1.5214844
1.5205078
−0.0051789
11
1.5205078
1.5214844
1.5209961
−0.0022794
12
1.5209961
1.5214844
1.5212402
−0.0008289
13
1.5212402
1.5214844
1.5213623
−0.0001034
14
1.5213623
1.5214844
1.5214233
0.0002594
15
1.5213623
1.5214233
1.5213928
0.0000780
Bisection Method Lecture Notes
of 3
Report
Tell us what’s wrong with it:
Thanks, got it!
We will moderate it soon!
Struggling with your assignment and deadlines?
Let EduBirdie's experts assist you 24/7! Simply submit a form and tell us what you need help with.